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3 years ago

7

A professor is examining a new strain of bacteria. The amount of bacteria can be modeled by function s(n) = 20 · bn, where n is

the number of hours and b is an unknown positive base.

1 answer:

torisob [31]3 years ago

8 0

Answer:

s(n) = 20

s = 20/n

Step-by-step explanation:

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When subtracting polynomials,distribute the negative sign,then add.

Doss [256]

Answer:

7m^2 - 11m - 2

Step-by-step explanation:

Subtract (-3m^2 + 10m + 4) from 4m^2 - m + 2:

4m^2 - m + 2

- (-3m^2 + 10m + 4) Now distribute the negative sign:

4m^2 - m + 2

+ 3m^2 - 10m - 4

--------------------------

7m^2 - 11m - 2 is the final answer.

5 0

3 years ago

Which is the value of 2.3 - (-2.3)?<br> A.23<br> B.0<br> C.4.6<br> D.-4.6

tresset_1 [31]

Answer:

B

Step-by-step explanation:

2.3 is being cancelled out.

5 0

3 years ago

Read 2 more answers

Omgggggggg PLZ HELP MEH I REALLY NEED HELP :'( IM FAILING MATH AND THIS WILL REALLY HELP ALL BELOW IM BEGGING YOU

faltersainse [42]

Answer:

1. -2w-1 cuz when in parethese it all become negative. 2. factors of 32 is 1,2,4,8,16,32. and factors of 24 is 1,2,3,4,6,8,12,24. and the way you should write 32k+24 is 4(8k+6)

Step-by-step explanation:

7 0

3 years ago

Cable Strength: A group of engineers developed a new design for a steel cable. They need to estimate the amount of weight the ca

KatRina [158]

Answer:

95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

Step-by-step explanation:

We are given that the engineers take a random sample of 45 cables and apply weights to each of them until they break. The mean breaking weight for the 45 cables is 768.2 lb. The standard deviation of the breaking weight for the sample is 15.1 lb.

Since, in the question it is not specified that how much confidence interval has be constructed; so we assume to be constructing of 95% confidence interval.

Firstly, the Pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean breaking weight = 768.2 lb

s = sample standard deviation = 15.1 lb

n = sample of cables = 45

$\mu$ = population mean breaking strength

Here for constructing 95% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

<u>So, 95% confidence interval for the population mean, </u> $\mu$ <u> is ;</u>

P(-2.02 < $t_4_4$ < 2.02) = 0.95 {As the critical value of t at 44 degree

of freedom are -2.02 & 2.02 with P = 2.5%}

P(-2.02 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.02) = 0.95

P( $-2.02 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.02 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.02 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.02 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

<u>95% confidence interval for</u> $\mu$ = [ $\bar X-2.02 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.02 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $768.2-2.02 \times {\frac{15.1}{\sqrt{45} } }$ , $768.2+2.02 \times {\frac{15.1}{\sqrt{45} } }$ ]

= [763.65 lb , 772.75 lb]

Therefore, 95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

3 0

3 years ago

What is -1.64 as a mixed number in simplest form??

cupoosta [38]

Answer:

the answer will be

-1 16/25

6 0

3 years ago