Given:
Intensity of earthquake is 5011 times more than
To find:
The magnitude of an earthquake that is 5011 times more than a standard earthquake.
Solution:
The magnitude of an earthquake:
where 
is the measured intensity of earthquake and
is the standard intensity of earthquake
Given 5011 times more than a standard earthquake.
Substitute this into the magnitude.
Cancel both in the numerator and denominator.
M = 3.7
The magnitude of the earthquake is 3.7.
Answer:
The ball will take 1 sec
Step-by-step explanation:
∵ The distance from the ground when the ball leaves = 6 ft
∵ The distance from the ground when the ball catches = 10 ft
∴ The difference between two position = 10 - 6 = 4 ft
∵ s = ut - 1/2 at² ⇒ s is the distance , u is the initial velocity , a is acceleration of gravity and t is the time
∵ s = 4 feet , u = 20 feet/sec and a ≅ 32 feet/sec²
∴ 4 = 20t -32/2 t²
∴ 16t² - 20t + 4 = 0
∴ (4t - 4)(4t - 1) = 0
∴ 4t - 4 = 0 ⇒ t = 1 and 4t - 1 = 0 ⇒ t = 1/4
∴ The ball will take 1 sec to go from first player to the second player
Note: 1/4 sec is the time of the ball after leaves the position of the first player by 4 feet above the initial position.
Answer:
9
Step-by-step explanation:
3^5 = 243
3^3 = 27
243 / 27 = 9
Hope this helps :)
