Line a passes through points (6, 10) and (1, 1). Line b is perpendicular to a. What is the slope of line b?
2 answers:
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A triangle solver tells you
C = 85°
b ≈ 8.4
c ≈ 10.4
From the sum of angles of a triangle,
C = 180° -42° -53° = 85°
From the law of sines
b = sin(53°)/sin(42°)*7 ≈ 8.355
c = sin(85°)/sin(42°)*7 ≈ 10.422
C = 85°
b ≈ 8.4
c ≈ 10.4
From the sum of angles of a triangle,
C = 180° -42° -53° = 85°
From the law of sines
b = sin(53°)/sin(42°)*7 ≈ 8.355
c = sin(85°)/sin(42°)*7 ≈ 10.422