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White raven [17]

3 years ago

10

Noah finished a word search in 3/4 the time it took David. And rays finished the word search in 2/3 the time it took Noah. David

finished the word search in 32 minutes. How long did it take Andraya to finish the word search?

1 answer:

DochEvi [55]3 years ago

6 0

Answer:

16

Step-by-step explanation:

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Please help! Marking brainliest if correct.

katrin2010 [14]

Answer:

110 degrees

Step-by-step explanation:

Because these angles are vertical, 5x+15=8x-42. thus, 15=3x-42, 3x=57, and x=19. 5x+15=5(19) +15=110. So, m<CDE=110 degrees.

7 0

3 years ago

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Question 10(Multiple Choice Worth 1 points) (06.01 LC) Choose the polynomial that is written in standard form.

Svetach [21]

Answer:

−3x^8 + 9x^2 + 10x

Step-by-step explanation:

A polynomial is in standard form when the exponents of the variable decrease left to right. The only given expression in that form is ...

−3x^8 + 9x^2 + 10x

7 0

2 years ago

(b) Create a sequence that begins with a negative rational number, is increasing by addition, and is infinite

fgiga [73]

Answer:

an infinite is a list or string of discrete objects, usually numbers, that can be paired off one-to-one with the set of positive integer s {1, 2, 3, ...}.

Step-by-step explanation:

6 0

2 years ago

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Solve the following quadratic equation by completing the square ✓3x^2 + 10x + 7✓3 = 0

solmaris [256]

$\sqrt{3}x^2+10x+7\sqrt{3}=0\\\\\sqrt3(x^2+\dfrac{10x}{\sqrt{3}}+7)=0\\\\x^2+\dfrac{10x}{\sqrt{3}}+7=0\\\\x^2+\dfrac{10x}{\sqrt{3}}+\dfrac{25}{3}-\dfrac{25}{3} +7=0\\\\(x+\dfrac{5}{\sqrt{3}})^2 = \dfrac{4}{3}\\\\|x+\dfrac{5}{\sqrt{3}}| = \dfrac{2}{\sqrt{3}}\\\\x_1 = \dfrac{2}{\sqrt{3}}-\dfrac{5}{\sqrt{3}} = -\dfrac{3}{\sqrt{3}} = -\sqrt{3}\\\\x_2 = -\dfrac{2}{\sqrt{3}}-\dfrac{5}{\sqrt{3}} = \dfrac{-7}{\sqrt{3}} = -\dfrac{-7\sqrt{3}}{3}$

5 0

3 years ago

Find k so that the distance from (–1, 1) to (2, k) is 5 units. k= k= *there are two solutions for 2*

dalvyx [7]

Answer:

k = -3

k =5

Step-by-step explanation:

$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d = 5\\(-1,1) =(x_1,y_1)\\(2,k)=(x_2,y_2)\\$

$5=\sqrt{\left(2-\left(-1\right)\right)^2+\left(k-1\right)^2}\\\\\mathrm{Square\:both\:sides}:\quad 25=k^2-2k+10\\25=k^2-2k+10\\\\\mathrm{Solve\:}\:25=k^2-2k+10:\\k^2-2k+10=25\\\\\mathrm{Subtract\:}25\mathrm{\:from\:both\:sides}\\k^2-2k+10-25=25-25\\k^2-2k-15=0\\\\\mathrm{Solve\:by\:factoring}\\\\\mathrm{Factor\:}k^2-2k-15:\quad \left(k+3\right)\left(k-5\right)\\\mathrm{Solve\:}\:k+3=0:\quad k=-3\\$

$\mathrm{Solve\:}\:k-5=0:\quad k=5\\\\k =5 , k=-3$

7 0

3 years ago

Read 2 more answers