The allele for the white flower is dominant, which is why more of the offspring were white.
<span>Glycolysis
4 made - 2 used= 2 ATP substrate level
2 NADH x 2= <span>4 ATP </span>(enters at complex II)
Pyruvate Decarboxylation
1 NADH x two pyruvate= 2 NADH x 3= 6 ATP
Krebs Cycle
3 NADH x two pyruvate= 6 x 3= 18 ATP
1 GTP x two pyruvate= 2 GTP= 2 ATP
1 FADH2 x two pyruvate= 2 FADH2 x2= 4 ATP
Total: 2+4+6+18+2+4= 36 ATP</span>
Answer:
a) Both DdPp
b) Yes 3.8%
c) In plant A, the dominant allele D and P are coupled (DP, dp), In plant B they are in repulsion (Dp, dP).
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