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mihalych1998 [28]
3 years ago
8

Solve the inequality.

Mathematics
1 answer:
Flauer [41]3 years ago
6 0
-2p<span><20-4
-2p</span><span><16
thus,
p</span><span>>-8</span>
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Fifteen more than four times a number is equal to the difference between 191 and four times the number. Find the number.
Semenov [28]

Answer:

The number would be 22.

Step-by-step explanation:

In order to solve for the number, we need to make both statements into numerical statements.

Fifteen more than four times a number = 15 + 4x

difference between 191 and four times the number = 191 - 4x

Now we set them equal to each other.

15 + 4x = 191 - 4x -----> Add 4x to each side

15 + 8x = 191 ------> Subtract 15 from both sides

8x = 176 -------> Divide by 8

x = 22

5 0
3 years ago
Can someone help me I think I'm doing my math wrong
Julli [10]

Answer:

Ay bruv I need to see the answer choices to help

Step-by-step explanation:

7 0
3 years ago
What is 5 2<br><img src="https://tex.z-dn.net/?f=%20%5Ctimes%20" id="TexFormula1" title=" \times " alt=" \times " align="absmidd
Feliz [49]
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8 0
3 years ago
4(3x+2y) distributive property pls help
Sonbull [250]

Answer:

12x+8y

Step-by-step explanation:

1) Expand by distributing terms.

4*3x+4*2y

2) Simplify 4*3x to 12x.

12x+4*2y

3) Simplify  4*2y to 8y.

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8 0
2 years ago
cos theta = 4/5, 0˚&lt; theta &lt; 90˚ use the information given to find sin2theta, cos2theta, and tan 2theta
NikAS [45]
First calculate \sin\theta.

\sin^2\theta+\cos^2\theta=1\\\\\sin^2\theta=1-\cos^2\theta\\\\\sin^2\theta=1-\left(\dfrac{4}{5}\right)^2\\\\\\\sin^2\theta=1-\dfrac{16}{25}\\\\\\\sin^2\theta=\dfrac{9}{25}\quad|\sqrt{(\dots)}\\\\\\\sin\theta=\sqrt{\dfrac{9}{25}}\\\\\\\boxed{\sin\theta=\dfrac{3}{5}}

We take positive value of sinθ because 0° < θ < 90°
Now we could calculate sin2θ, cos2θ and tan2θ:

\sin2\theta=2\sin\theta\cos\theta=2\cdot\dfrac{3}{5}\cdot\dfrac{4}{5}=\dfrac{2\cdot3\cdot4}{5\cdot5}=\dfrac{24}{25}\\\\\\\cos2\theta=\cos^2\theta-\sin^2\theta=\left(\dfrac{4}{5}\right)^2-\left(\dfrac{3}{5}\right)^2=\dfrac{16}{25}-\dfrac{9}{25}=\dfrac{7}{25}\\\\\\&#10;\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=\dfrac{\frac{24}{25}}{\frac{7}{25}}=\dfrac{24\cdot25}{7\cdot25}=\dfrac{24}{7}=3\dfrac{3}{7}
5 0
3 years ago
Read 2 more answers
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