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Lubov Fominskaja [6]
2 years ago
6

Is it a way to get robuc 4 free

Computers and Technology
2 answers:
MAVERICK [17]2 years ago
7 0

Answer:

→ i am not sure what your question says but i think it says is their a way to get ro bux for free , and i am not sure but (i hope you have a nice day or night !!!!!! :))).

VLD [36.1K]2 years ago
3 0

Answer:

yes you do survays

Explanation:

You might be interested in
Weak Induction
slega [8]

Answer:

Following are the answer to this question:

Explanation:

In option 1:

The value of n is= 7, which is (base case)

\to 3^7

when n=k for the true condition:

\to 3^k

when n=k+1 it tests the value:

\to 3^{(k+1)}= 3^k,3\\\to < (k!) 3 \ substituting \ equation \\\to

since k>6  hence the value is KH>3 hence proved.

In option 2:

when:

for n=1:(base case)

\log(1!)

0<=0 \\ condition is true

when the above statement holds value n=1

when n=k

\log(k!)

when n=k+1

\log(k+1)!=\log(k!)+\log(k+1)\\

             

\because k \log k      [\therefore KH>K \Rightarrow  \log(KH>\loK)]

In option 3:

when n=1:

A_1 \cup B=A_1 \cup B\\\\

when n=k

\to (A_1\cap A_2 \cap.....A_k) \cup B\\=(A_1\cup B) \cap(A_2\cup B_2)....(A_k \capB).....(a)\\\to n= k+1\\ \to (A_1\cap A_2 \cap.....A_{kH}) \cup B= (A_1\cup B)\\\\\to  [(A_1\cap A_2 \cap.....A_{k}) \cup B]\cap (A_{KH}\cup B)\\\\\to  [(A_1\cup B) \cap (A_2 \cup B) \cap (A_3\cup B).....(A_k\cup B)\cap (A_{k+1} \cup B)\\\\  \ \ \ \ \ \ substituting \ equation \ a \\\\

hence n=k+1 is true.

7 0
3 years ago
A large number of genetic codes are stored as binary values in a list. Which one of the following conditions must be true in ord
Bad White [126]

Answer:

D

Explanation:

3 0
3 years ago
Read 2 more answers
Write a c program that reprints input so that no line is longer than 50 characters. Specifically, for lines less than or equal t
Alex73 [517]

Using the knowledge in computational language in C++ it is possible to write a code that reprints prints input so that no line is longer than 50 characters.

<h3>Writting the code:</h3>

<em>#include<stdio.h></em>

<em />

<em>int main(int argc, char** argv){</em>

<em>    //creating pointer to read a file</em>

<em>    FILE * fp;</em>

<em>    char * line = NULL;</em>

<em>    size_t len = 0;</em>

<em>    ssize_t read;</em>

<em>    int i=0;</em>

<em>    //opening a file</em>

<em>    fp = fopen(argv[1], "r");</em>

<em>    //handling the error condition</em>

<em>    if (fp == NULL){</em>

<em>        printf("File not found..!!");</em>

<em>        return 0;</em>

<em>    }</em>

<em>    int moreThan50 =0;</em>

<em>    //reading a file line by line</em>

<em>    while ((read = getline(&line, &len, fp)) != -1) {</em>

<em>        i = 0;</em>

<em>        if(read >= 50){</em>

<em>            moreThan50++;</em>

<em>        }</em>

<em>        while(i < read){</em>

<em>            if(line[i]!='\n'){</em>

<em>                if(i%50 == 0){</em>

<em>                    printf("\n%c",line[i]);</em>

<em>                }else{</em>

<em>                    printf("%c",line[i]);</em>

<em>                }</em>

<em>            }</em>

<em>            i++;</em>

<em>        }</em>

<em>    }</em>

<em>    printf("\nTotal lines over 50 chars: %d\n",moreThan50);</em>

<em>    printf("Offending Lines: ");</em>

<em>    for(i=1;i<=moreThan50;i++)</em>

<em>        printf("%d, ",i);</em>

<em>    fclose(fp);</em>

<em>    return 0;</em>

<em>}</em>

See more about C++ at brainly.com/question/19705654

#SPJ1

4 0
1 year ago
What is the usual price of smartphone apps?
natka813 [3]

0-20 dollars

that's the usual cost for apps

and for phone it's cost

RS 32,000 Nepali rupes

you can convert it by dividing it by 110

and you will get price in dollars

8 0
3 years ago
Read 2 more answers
What defines "print media"? It is media that includes words and text rather than video, such as many blogs. It is media that is
uranmaximum [27]

Answer:

"It is media that is distributed in paper form, such as magazines and newspapers."

3 0
3 years ago
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