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Soloha48 [4]
3 years ago
7

Help!!!! If you wanted to model movements with both of the robot's arms in the air, what function

Mathematics
1 answer:
mixas84 [53]3 years ago
3 0

Answer:

f(x)=x^2

Step-by-step explanation:

if you wanted have a function where both of the robot's arms are in the air the function could be x to the power of any even number such f(x)=x^2, f(x)=x^4, f(x)=x^6, or even f(x)=x^10. And you could still do the same transformations with these equations.

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Ben drives 405 miles on 15 gallons. How many miles does Ben drive on one gallon?
wel

Answer:

B. 27 miles per gallon

Step-by-step explanation:

In order to solve for this, you just have to divide:

\frac{405}{15} =27

Hopefully I helped :)

6 0
3 years ago
How far apart are the 2 cities? See picture. <br> Show steps
Gennadij [26K]

9514 1404 393

Answer:

  373 miles

Step-by-step explanation:

The difference in latitude is ...

  39.1° -33.7° = 5.4° = 0.54°(π/180°) radians = 0.03π radians

The arc length is given by ...

  s = rθ, where θ is the angle in radians

The length of the arc along the longitude line is ...

  s = (3960 mi)(0.03π) ≈ 373 mi

The distance from Atlanta to Cincinnati is about 373 miles.

6 0
3 years ago
Put these in order of size smallest first 60% 0.4 1/2
Ludmilka [50]
.4 is smallest, 1/2 , then 60% is greatest.
3 0
3 years ago
Read 2 more answers
HELLO!! I NEED HELP! Please show full Solutions. I will mark brainliest for the best answer. Thank you and god bless.
Greeley [361]
((x+2)(x+2))-((x-5)(1))=A

x^2+4x+4-x+5=A

x^2+3x+9=A
8 0
3 years ago
Car A, traveling at a constant 10 m/s, crosses the start line 3 seconds before Car B, who is traveling at a constant 15 m/s. At
Margaret [11]
The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
 
Distance traveled by car A =x,  (when the car B is at the same distance from the start line)
time of car A=t

x=10 m/st  ⇒    x=10t    (1)

Distance traveled by car B=x
time of car B=t-3

x=15(t-3)  (2)

With the equations (1) and (2) we make a system of equations:

x=10t
x=15(t-3)

We solve this system of equations:

10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9

t-3=9-3=6

x=10 t=10 (9)=90

Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
8 0
3 years ago
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