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Setler79 [48]
3 years ago
8

A plane travels 3,625.26 miles in 6.9 hours. What is the plane’s unit rate?

Mathematics
1 answer:
Lunna [17]3 years ago
5 0

Answer:

The correct answers are:

a)\frac{3625.26 miles}{6.9hours}

b)36252.6 tenths miles÷ 69 tenths hours

c)\frac{3500miles}{7hours}= 500\frac{miles}{hour}

d)\frac{3625.26miles}{6.9hours} \frac{10}{10} =\frac{36252.6miles}{69hours}

e) 525.4 miles/h

Step-by-step explanation:

The division is solved by using the division algorithm in the attached picture.

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Enter your answer and show all the steps that you use to solve this problem in the space provided. Find the values of x and y.
satela [25.4K]

Answer : The value of x and y is, 90^o and 43^oC

Step-by-step explanation :

First we have to calculate the angle B.

As we know that,

The given triangle is an isosceles triangle in which the angles opposite to equal sides are always equal.

Thus, \angle B=\angle C

Given : \angle C=47^o

\angle B=\angle C=47^o

\angle B=47^o

Now have to calculate the angle A.

As we know that the sum of interior angles of a triangle is equal to 180^o.

\angle A+\angle B+\angle C=180^o

\angle A+47^o+47^o=180^o

\angle A+94^o=180^o

\angle A=180^o-94^o

\angle A=86^o

Now we have to determine the angle y.

As we know that, line AD is an angle bisector. That means, it divides into two equal angles. So,

\angle y=\frac{\angle A}{2}

\angle y=\frac{86^o}{2}

\angle y=43^o

Now we have to determine the angle x.

As we know that the sum of interior angles of a triangle is equal to 180^o.

\angle y+\angle B+\angle x=180^o

43^oc+47^o+\angle x=180^o

\angle x+90^o=180^o

\angle x=180^o-90^o

\angle x=90^o

Thus, the value of x and y is, 90^o and 43^oC

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2 years ago
Please Answer Quick i'm in a rush please ill give brainliest!!!!!!!
valentina_108 [34]

Answer:

roy is in the same quadrant

Step-by-step explanation:

↙↘⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵

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4.5 meters equals how many centimeters
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\text{Put the value of x to the expression}\\\\\sqrt{x+3};\ x=15\\\\\sqrt{15+3}=\sqrt{18}=\sqrt{9\cdot2}=\sqrt9\cdot\sqrt2=\boxed{3\sqrt2}


\text{Put the value of x to the expression}\\\\\dfrac{6}{\sqrt{x}},\ x=3\\\\\dfrac{6}{\sqrt3}=\dfrac{6\cdot\sqrt3}{\sqrt3\cdot\sqrt3}=\dfrac{6\sqrt3}{3}=\boxed{2\sqrt3}


\text{Put the value of x to the expression}\\\\4\sqrt{x+1}-3\sqrt{2x+6},\ x=3\\\\4\sqrt{3+1}-3\sqrt{2(3)+6}=4\sqrt4-3\sqrt{6+6}=4(2)-3\sqrt{12}\\\\=8-3\sqrt{4\cdot3}=8-3\sqrt4\cdot\sqrt3=8-3(2)\cdot\sqrt3=\boxed{8-6\sqrt3}

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