How to graph 9x+15y=45

1 answer:

3 0

First you should rearrange to get it in the form y = mx + c, and you do this by subtracting the 9x from both sides and dividing by 15, which gives you:
y = (-9/15)x + 3

Now you know the y-intercept is 3, so you can mark that on as a point.
Then, to graph the gradient of -9/15, you go along 15 spaces to the right and 9 spaces down, or 15 to the left and 9 spaces up, and you repeat this until you run out of room. Then you just join the dots

I hope this helps! Let me know if you have any questions :)

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The Solution for the given system of equations is (-2) and $(\frac{5}{3})$ .

The given are linear equations as follow:
y = $\frac{2}{3}x$ + 3 .. ... ...(1)
and x = -2. .. .... ...(2)

We already know the first part of the solution (x) which is -2. We can find the other part (y) by putting the value of equation (2) in equation (1).

By putting the values of x in equation (1), we get

y = $(\frac{2}{3})(-2)$ + 3
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Taking the L. C. M of denominators which will be '3', we get:

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So the second part (y) of the solution of the given equation is $\frac{5}{3}$ .

Hence, the overall solution to the given system of equation is $(-2, \frac{5}{3})$ .

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