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lawyer [7]
3 years ago
15

By , cos(θ) = StartFraction x Over r EndFraction, and by , sin(θ) = StartFraction y Over r EndFraction. Multiplying both sides o

f the above equations by r, we get that x = r cos(θ) and y = r sin(θ). The states that x2 + y2 = r2. By , we have [r cos(θ)]2 + [r sin(θ)]2 = r2. Applying the , the equation can be written as r2 cos2(θ) + r2 sin2(θ) = r2. Dividing both sides of the equation by r2 results in cos2(θ) + sin2(θ) = 1.
Mathematics
1 answer:
Marianna [84]3 years ago
8 0

Answer:

definition of cosine, definition of sine, pythagorean theorem, substitution, laws of exponents.

Step-by-step explanation:

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Solve the following:<br> a) 4x 3= 2x + 7<br><br> b) 2x+6= 7x14
nikdorinn [45]
<h2><u>Correct question</u> : 4x - 3 = 2x + 7 </h2>

<h2><u>Solution</u> : 4x - 3 = 2x + 7 </h2>

4x - 2x = 7 + 3 \\  \\ 2x = 10 \\  \\ x =  \frac{10}{2}  \\  \\ x = 5.

<h2>•••••••••••••••••••••••••••••••••••••••</h2>

<h2><u>Correct Question</u> : 2x + 6 = 7x - 14</h2>

<h2><u>Solution</u> : 2x + 6 = 7x - 14</h2>

2x - 7x =  - 14 - 6 \\  \\  - 5x =  - 20 \\  \\ x =  \frac{20}{5}  \\  \\ x = 4.

7 0
1 year ago
Determine if the function is continuous to its domain
Maurinko [17]

Yes, it is continuous to its domain

<h2>Explanation:</h2><h2></h2>

In order to find the domain of the function we need to get the restrictions:

1. From natural log:

x>0

2. From quotient:

x\neq 0

Matching these two restrictions the domain is:

x\in (0,\infty)

So the function is continuous to its domain because is defined for every x-value in the interval (0, \infty))

<h2>Learn more:</h2>

Functions: brainly.com/question/12891789

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6 0
3 years ago
Renee is simplifying the expression (7) (StartFraction 13 over 29 EndFraction) (StartFraction 1 over 7 EndFraction). She recogni
dsp73

Answer:

The correct option is commutative property.

Step-by-step explanation:

The expression that Renee is simplifying is:

(7)\cdot(\frac{13}{29})\cdot(\frac{1}{7})

It is provided that, Renee recognizes that 7 and \frac{1}{7} are reciprocals, so she would like to find their product before she multiplies by \frac{13}{29}.

The associative property of multiplication states that:

a\times b\times c=(a\times b)\times c=a\times (b\times c)

The commutative property of multiplication states that:

a\times b\times c=a\times c\times b=c\times a\times b

The distributive property of multiplication states that:

a\cdot (b+c)=a\cdot b+a\cdot c

The identity property of multiplication states that:

a\times 1=a\\b\times 1=b

So, Renee should use the commutative property of multiplication to find the product of 7 and \frac{1}{7},

(7)\cdot(\frac{13}{29})\cdot(\frac{1}{7})=(7\times\frac{1}{7})\times\frac{13}{29}=\frac{13}{29}

Thus, the correct option is commutative property.

5 0
3 years ago
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Multiply 0.75 by 100

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Help!!!!!!<br> Please and thank you
fenix001 [56]

Answer:

1. A

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Step-by-step explanation:

Hope this helps!

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