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vazorg [7]
3 years ago
10

Which is the slope-intercept form of an equation for the line containing

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
6 0

Answer:

The answer is letter A.

Step-by-step explanation:

y=mx+b

-3=(-1)(0)+b

-3=0+b

0 0

-3=b

y= -1x-3

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Which number represents 778, 332 rounded to the nearest thousand​
Fudgin [204]
The answer would be 778000.

Find the number in the thousand place
8 and look one place to the right for the rounding digit
3. Round up if this number is greater than or equal to
5 and round down if it is less than 5.

778000
8 0
3 years ago
A simplified model for the movement of the price of a stock supposes that on each day the stock’s price either moves up 1 unit w
DanielleElmas [232]

Answer:

(a) The probability that after 2 days the stock will be at its original price is

P_a=2p(1-p)

(b) The probability that after 3 days the stock’s price will have increased by 1 unit is

P_b=3p^2(1-p)

(c) Given that after 3 days the stock’s price has increased by 1 unit, the probability that it went up on the first day is

P=2/3

Step-by-step explanation:

(a) What is the probability that after 2 days the stock will be at its original price?

For the price of the stock to be in its original price, there are two ways it can happen:

1) the price increases the first day by one unit and decreases by one unit the second day. The probability of this event is P=p*(1-p).

2) the price decreases the first day by one unit and increases by one unit the second day. The probability of this event is P=(1-p)p.

The probability that after 2 days the stock will be at its original price is the sum of the probability of this two events:

P=P_1+P_2=p(1-p)+(1-p)p=2p(1-p)

(b) What is the probability that after 3 days the stock’s price will have increased by 1 unit?

For this event to happen (one unit increase in 3 days), it must have happened 2 increases in price and 1 decrease.

There are 3 possible ways of this to happen:

1) decrease in the first day.

2) decrease in the second day.

3) decrease in the third day.

Each one ot this 3 events has the same probability P_i=p^2(1-p).

So the probability that after 3 days the stock’s price will have increased by 1 unit is equal to the sum of the probabilities of this events:

P=P_1+P_2+P_3=3p^2(1-p)

(c) Given that after 3 days the stock’s price has increased by 1 unit, what is the probability that it went up on the first day?

According to the answer (c), there are 3 events where the price has increase by one unit after 3 days, each one with equal probability P_i=p^2(1-p).

Of these 3 events, there are 2 that have an increase in the first day. So we can conclude that, if the events have the same probability, the probability of the increase in the first day, given that the price has increased by one unit in 3 days, is P=2/3.

8 0
4 years ago
Need some help well give Brainliest if you answer right
xenn [34]

If this is asking 5% of $530 then the answer is 26.5

If this is asking that 530 is 5% then the answer is 10600

3 0
3 years ago
Suppose that 30% of all students who have to buy a text for a particular course want a new copy (the successes!), whereas the ot
Softa [21]

Answer:

a. Mean = 4.5, Standard Deviation = 1.775

b. 0.0152

Step-by-step explanation:

Given

n = 15 purchasers

p = Success = 30%

p = 0.3

q =Failure = 70%

q = 0.7

a.

Mean = np

Mean = 15 * 0.3

Mean = 4.5

Standard Deviation = √Variance

Variance = npq

Variance = 15 * 0.3 * 0.7

Variance = 3.15

Standard Deviation = √3.15

Standard Deviation = 1.774823934929884

Standard Deviation = 1.775 ---------- Approximated

b.

The probability that the number who want new copies is more than two standard deviations away from the mean value

Standard Deviation = 1.775

Mean = 4.5

2 Standard Deviation and Mean = 2 * 1.775 + 4.5

= 3.55 + 4.5

= 8.05

P(X>8.05) = P(9) + P(10) +........+ P(15)

Using the binomial distribution

(p + q) ^ n where p = 0.3, q = 0.7 , n = 15

Expanding (p+q)^n where n = 15 and r > 8

We have

15C9 p^9 q^6 + 15C10 p^10 q^5 + 15C11 p^11 q⁴ + 15C12 p^12 q³ + 15C13 p^13 q² + 15C14 p^14 q + p^15

= 5005 (0.3)^9 (0.7)^6 + 3003 (0.3)^10 (0.7)^5 + 1365 (0.3)^11 (0.7)⁴ + 455 (0.3)^12 (0.7)³ + 105 (0.3)^14 (0.7)² + 15 (0.3)^14 (0.7) + 0.3^15

=0.015234

7 0
3 years ago
-6 is less than or equal to 2x - 12 is less than 20
denis23 [38]
-6 is less than or equal to 2x - 12 is less than 20

7 0
3 years ago
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