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serg [7]
3 years ago
6

What is the vertex on a right angle

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
6 0

The vertex would be the point on the right angle like the tip of the right angle

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Write 12 digit whole numbers with the following digits in correct places
lbvjy [14]

Answer:

29,675,000

Step-by-step explanation:

i’m sorry if this is wrong but i think it’s right

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3 years ago
Find the perimeter and area
Nitella [24]

Answer:

Step-by-step explanation:  Perimeter is distance around the outside so 8+8+5+5=26 units

Area - I'll get  back with you

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3 years ago
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Brainliest if Correct!! Help QUICK....
Sloan [31]

Replace x with the x value solve to get the y value.


see attached picture for answers.

6 0
2 years ago
I need answers!!!!!!!!
aleksandrvk [35]

Answer:

a) 4.4583 b) Fiona

Step-by-step explanation:

First find the average of the numbers by adding them all together then dividing them by the amount of numbers given:

(85 + 88 + 90 + 91 + 93 + 96 + 97 + 97 + 98 + 98 + 99 + 105)\div12= 1137\div12= 94.75

Then find the difference between each number and the answer you got

(85 - 94.75) + (88 - 94.75) + (90 - 94.75) + (91 - 94.75) + (93 - 94.75) + (96 - 94.75) + (97 - 94.75) + (97 - 94.75) + (98 - 94.75) + (98 - 94.75) + (99 - 94.75) + (105 - 94.75)\div12

Which is

(9.75) + (6.75) + (4.75) + (3.75) + (1.75) + (1.25) + (2.25) + (2.25) + (3.25) + (3.25) + (4.25) + (10.25)\div12

Which comes out to

\frac{53.5}{12}=4.4583

6 0
3 years ago
The position vector of p (relative to the origin) is op = (x, y). if the magnitude of op is 5 units, find the set of all possibl
Firdavs [7]

Answer:

S = {(0, 5), (0, - 5), (3, 4), (3, -4), (-3, 4), (-3, -4), (4, 3), (4, -3), (-4, 3), (-4, -3), (5,0), (-5, 0) }

Step-by-step explanation:

Remember that the distance between two points (a, b) and (c, d) is given by:

distance = \sqrt{(a - c)^2 + (b - d)^2}

So, here we have that the distance between the point (x, y) and the origin, (0, 0) must have a magnitude of 5 units, then we want to solve:

5 = \sqrt{(x - 0)^2 + (y - 0)^2} \\5 = \sqrt{x^2 + y^2}

If we square both sides, we get

5^2 = (\sqrt{x^2 + y^2} )^2\\25 = x^2 + y^2

Now we want to find all the points (x, y) that meet this condition, suc that:

x ∈ Z

y ∈ Z

So both x and y must be integers.

So here we can just play with different values of x and y.

For example, if we define:

x = 0 we get:

25 = 0^2 + y^2

25 = y^2

√25 = y

Then we can have y = 5 or  y = -5

from this we got two points:

(0, 5) and (0, - 5)

if x = 1 we have:

25 = 1^2 + y^2

25 - 1 = y^2

24 = y^2

There is no integer such that its square is equal to 24, so we can stop here.

if x = 2 or - 2, we have:

25 = 2^2 + y^2

25 = 4 + y^2

25 -4 = 21 = y^2

Again, there is no integer such that its square is equal to 21, so we can stop here.

if x = +3 or -3, we have:

25 = 3^2 + y^2

25 = 9 + y^2

25 - 9 = 16 = y^2

√16 = y

then we can have y = 4 or y = -4

from this we got four points:

(3, 4)

(-3, 4)

(3, -4)

(-3, -4)

And for symmetry, if x = 4 or -4 we have the points:

(-4, 3)

(4, 3)

(-4, -3)

(4, -3)

finally, again for symmetry, if we take x = 5 or x = -5 we have the points:

(5,0)

(-5, 0)

Concluding, the set of all possible values (x, y) is:

S = {(0, 5), (0, - 5), (3, 4), (3, -4), (-3, 4), (-3, -4), (4, 3), (4, -3), (-4, 3), (-4, -3), (5,0), (-5, 0) }

7 0
3 years ago
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