Answer:
16 = 2n
Step-by-step explanation:
16 = 2n
16 ÷ 2 = 2n ÷ 2
n = 8
Answer:
Due to the location of the marker, it is closest to:
C.) 10/16 = 5/8 lb.
Each pound is divided into 16ths since 10 sixths are represented by the marker then the answer would be 10/16.
10 / 16 = 5 / 8
10 divided by 2 = 5
----------------------------
16 divided by 2 = 8
Therefore 10 / 16 = 5 / 8.
Step-by-step explanation:
Have a great rest of your day
#TheWizzer
Answer:
0.75417552
reduced equals 0.75
Step-by-step explanation:
log(55/2)
log(81)
Decimal Form: 0.7541755
this answer is the anser if you are dividing log 10 and 27 1/3 by log 10 81
Alright, lets get started.
The length of each section what carpenter needs to cut is 3 feet and 8 inches.
Converting 3 feet and 8 inches into feet only, we know, 
So, 3 feet 8 inches = 
feet
It means length of each section = 
feet
Carpenter needs to cut 4 sections, so length of 4 sections will be = 
2/3 feet means 8 inches so she needs board 14 feet 8 inches
Board is only sold by the feet only so, she has to puchase 15 feet board. : Answer
Hope it will help :)
So you can do this multiple ways, I'll do this the way that I think makes sense the l most easily.
Cos (0) = 1
Cos (pi/2)=0
Cos (pi) =-1
Cos (3pi/2)=0
Cos (2pi)=1
Now if you multiply the inside by 4, the graph oscillates more violently (goes up and down more in a shorter period).
But you can always reduce it.
Cos (0)= 1
Cos (4pi/2) = cos (2pi)=1
Cos (4pi) =Cos (2pi) =1 (Any multiple of 2pi ==1)
etc...
the pattern is that every half pi increase is now a full period as apposed to just a quarter of one. That's in theory.
Now that you know that, the identities of Cosine are another beast, but mathematically.
You have.
Cos (2×2t) = Cos^2 (2t)-Sin^2 (2t)
Sin^2 (t)=-Cos^2 (t)+1..... (all A^2+B^2=C^2)
Cos (2×2t) = Cos^2 (t)-(-Cos^2 (t)+1)
Cos (2×2t)= 2Cos^2 (2t) - 1
2Cos^2 (2t) -1= 2 (Cos^2(t)-Sin^2(t))^2 -1
(same thing as above but done twice because it's cos ^2 now)
convert sin^2
2Cos^2 (2t)-1 =2 (Cos^2 (t)+Cos^2 (t)-1)^2 -1
2 (2Cos^2(t)-1)^2 -1
2 (2Cos^2 (t)-1)(2Cos^2 (t)-1)-1
2 (4Cos^4 (t) - 2 (2Cos^2 (t))+1)-1
Distribute
8Cos^4 (t) -8Cos^2 (t) +1
Cos (4t) =8Cos^4-8Cos^2 (t)+-1
