Can you guys plz help me
1 answer:
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The complete question in the attached figure
step 1
find the area of the wall
[area of the wall]=[area of rectangle]+[area of triangle]
[area of the wall]=[3*2]+[3*1/2]----> 7.5 m²
1 m²-------> 10.7639 ft²
area of the wall------> 7.5*10.7639------> 80.73 ft²
we know that
1 can of paint covers an area of --------> 24 ft²
x---------------------------------------------> 80.73 ft²
x=80.73/24---------> x=3.36 can of paints
the answer is
T<span>he fewest number of cans is 4</span>
step 1
find the area of the wall
[area of the wall]=[area of rectangle]+[area of triangle]
[area of the wall]=[3*2]+[3*1/2]----> 7.5 m²
1 m²-------> 10.7639 ft²
area of the wall------> 7.5*10.7639------> 80.73 ft²
we know that
1 can of paint covers an area of --------> 24 ft²
x---------------------------------------------> 80.73 ft²
x=80.73/24---------> x=3.36 can of paints
the answer is
T<span>he fewest number of cans is 4</span>
Answer:
1008
Step-by-step explanation:
like the 2nd picture we split it in 3 rectangular prism
=6*7*8=336
=6*7*8=336
=6*7*8=336
V=336+336+336=1008
The Law of Sines says
We don't have to worry about the obtuse supplement because a triangle can only have one obtuse angle, and that's B.
Answer: A=29.44°, C=34.96°