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Mumz [18]
2 years ago
8

Helpp me with this.. answer this

Mathematics
1 answer:
EleoNora [17]2 years ago
4 0

Answer: ?????? What is that

Step-by-step explanation:

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Ughh i suck at dilation
Ivenika [448]
Look at!!:
Pre image  A(3,4), B(1,5) C(6,6);
If you multiply these coordinates by 3/2, you get its images:

A(3,4)              ⇒ A`(3*3/2, 4*3/2)=(4.5, 6)
B(1,5)              ⇒B`(1.*3/2,  5*3/2)=(1.5, 7.5)
C(6,6)              ⇒C`(6*3/2, 6*3/2)=(9,9)

Therefore the scale factor is 3/2. 
When the scale factor of a dilation is >1, then we have an enlargement, an expansion.
In this case 3/2=1.5>1

Answer: 

The dilation is expansion.
The scale factor is 3/2. 
7 0
3 years ago
An acute triangle had two sides measuring 8cm and 10 cm what is the best representation of the possible range of values for tge
katrin2010 [14]
The third side must be >2 and < 18

To test if a triangle is acute, right or obtuse:
1) Square all 3 sides
2) Sum the squares of the 2 shortest sides
3) Compare this sum to side 3 squared
if sum > side 3 squared it is an acute triangle
if sum = side 3 squared it is a right triangle
if sum < side 3 squared it is an obtuse triangle

The shortest side 2 can be is "less than 2" so we'll say it is 2.00000001
three sides squared =
<span> <span> <span> 4.00000004 </span> </span> </span>
64
100
Summing the 2 shortest sides 4.00000004 + 64 = <span>68.00000004
</span><span>68.00000004 is less than 100 so it is an obtuse triangle no matter how long the third side is.

</span>
8 0
3 years ago
Which of the following conditions must be met to conduct a two-proportion significance
katrin [286]

Hello, I Am BrotherEye

Answer: C.) 111 Only

Step-by-step explanation:

7 0
2 years ago
Graph y &gt; -1/3x+5<br><img src="https://tex.z-dn.net/?f=y%20%3E%20%20-%20%20%5Cfrac%7B1%7D%7B%203%20%7D%20x%20%2B%205" id="Tex
ad-work [718]

Explanation:

The function is y>-\frac{1}{3} x+5

To graph the function, let us find the x and y intercepts.

To find x-intercept, let us substitute y=0 in the function y>-\frac{1}{3} x+5

\begin{aligned}0 &=-\frac{1}{3} x+5 \\-5 &=-\frac{1}{3} x \\x &=15\end{aligned}

Thus, the x-intercept is (15,0)

To find the y-intercept, let us substitute x=0, we get,

\begin{aligned}&y=-\frac{1}{3}(0)+5\\&y=5\end{aligned}

Thus, the y-intercept is (0,5)

The graph has no asymptotes.

To plot the points in the graph, we need to substitute the values for x in the function y>-\frac{1}{3} x+5, to find the y-values.

The points are (-2,5.667),(-1,5.333),(1,4.667),(2,4.333),(3,4). The image of the graph and table is attached below:

6 0
2 years ago
Help me please it’s question 33
shtirl [24]
I don’t see anything. What is the problem.
8 0
3 years ago
Read 2 more answers
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