Answer:
16.2, 18,2, 20.2, 22.2, 24.2
Step-by-step explanation:
Let
represent an even interger.
Remeber that even intergers have a distance of 2 from each other.
So next four consecutive intergers are
and
Part 2: Five consective intergers have a sum of 101, and qe must find the numbers so
Answer:
a) The variable, M represents the amount of fish Ms. Montesinos has
b) The set equation is 11 + 2 = 3 × M - 2
c) 5
Step-by-step explanation:
The given parameters are;
The number of fishes in Ms. Cruz's tank = 11 fishes
The number of fishes Ms, Cruz has after buying two more fishes = 3 × The amount of fish Ms. Montesinos has - 2 fishes
a) Let the variable, M represent the amount of fish Ms. Montesinos has
b) The set up equation is as follows;
11 + 2 = 3 × M - 2
c) From the equation, 11 + 2 = 3 × M - 2, we have;
13 = 3·M - 2
3·M = 13 + 2 = 15
3·M = 15
M = 15/3 = 5
M = 5
The number of fishes Ms. Montesinos has is 17 fishes
Answer: The LCM of 15 and 6, so the least common multiple, the smallest multiple that they have in common, we see over here. 15 times 2 is 30. And 6 times 5 is 30.
