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blondinia [14]
2 years ago
7

What is the common difference in this equation? f(n) = 7n + 2

Mathematics
1 answer:
alekssr [168]2 years ago
7 0
The common difference is 2
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What two numbers multiply to -24 but also add to 22?
marta [7]

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-11 x2 =-22 -2 =24

Step-by-step explanation:

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Last night, the two dinner specials at Henry's favorite restaurant were salmon filet and steak. The restaurant served 55 special
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Since 11 out of 55 specials were salmon filet,

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Let g(x)=Intragal from 0 to x f(t) dt, where r is the function whos graph is shown.
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If

\displaystyle g(x) = \int_0^x f(t) \, dt

then g(x) gives the signed area under f(x) over a given interval starting at 0.

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since the integral of any function over a single point is zero;

\displaystyle g(4) = \int_0^4 f(t) \, dt = 8

since the area under f(x) over the interval [0, 4] is a right triangle with length and height 4, hence area 1/2 • 4 • 4 = 8;

\displaystyle g(8) = \int_0^8 f(t) \, dt = 0

since the area over [4, 8] is the same as the area over [0, 4], but on the opposite side of the t-axis;

\displaystyle g(12) = \int_0^{12} f(t) \, dt = -8

since the area over [8, 12] is the same as over [4, 8], but doesn't get canceled;

\displaystyle g(16) = \int_0^{16} f(t) \, dt = 0

since the area over [12, 16] is the same as over [0, 4], and all together these four triangle areas cancel to zero;

\displaystyle g(20) = \int_0^{20} f(t) \, dt = 24

since the area over [16, 20] is a trapezoid with "bases" 4 and 8, and "height" 4, hence area (4 + 8)/2 • 4 = 24;

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since the area over [20, 24] is yet another trapezoid, but with bases 8 and 12, and height 4, hence area (8 + 12)/2 • 4 = 40, which we add to the previous area.

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2 years ago
I need help plzzz it is due in 5 minutes
gladu [14]

Answer:

Just tried this on a calculator

)) i think its 7/2!

Step-by-step explanation:

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Factor the expression using GCF of 4+22​
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Answer:

the answer would be 2(2+11)

Step-by-step explanation:

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