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notsponge [240]
3 years ago
7

Please help I'm confused

Mathematics
1 answer:
9966 [12]3 years ago
3 0

Answer:

A, there is a 50% chance of getting heads than tails.

Step-by-step explanation:

B would have a 12% chance of that.

C would have a 43% chance since it kind of still in the winter zone but near summer...

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X+4/4=x/x-2<br> A:{-4,2} <br> B:{-2,4}<br> C:{}
Andreyy89

Answer:

<u>The correct answer is B. {-2,4}</u>

Step-by-step explanation:

Let's solve for x, this way:

x + 4/4 = x /x -2

(x + 4) * ((x - 2) = 4 * x

x² - 2x + 4x -8 = 4x

x² - 2x + 4x -8 - 4x = 0

x² - 2x  -8 = 0

(x - 4) * (x +2) = 0

x - 4 = 0

x + 2 = 0

x₁ = 4

x₂ = - 2

<u>The correct answer is B. {-2,4}</u>

3 0
3 years ago
(15 points) plz ay help would be appreciated and brainly will be given to best answer/for e-f find the value of x,y.z in each fi
Savatey [412]

Answer:

For E, each angle is 60° because its an equilateral triangle.

F is 45° for x, 135° for y, lastly z is 22.5°

7 0
3 years ago
Simplify 2 to the power of 4 times 2 to the power of 6
Marat540 [252]

Answer:

1/4

Step-by-step explanation:

=2^4×2^-6

=2^-2

=1/4

5 0
3 years ago
Read 2 more answers
P over 2 minus 5 when p = 14
bezimeni [28]

Answer: (14/2)-5=2

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Suppose that one pe
ElenaW [278]

Answer:

The probability that someone who tests positive has the genetic disease is approximately 0.166 or 16.6% who tests positive actually has the disease

Step-by-step explanation:

The number of persons in 10,000 people that have the disease = One

The percentage of people with the disease that test positive = 99.6%

The percentage of people who do not have the disease test positive = 0.05%

The probability that someone who tests positive has the genetic disease

P(disease | positive) = \dfrac{P(disease) \cdot P(positive | disease)}{P(disease) \cdot P(positive | disease) + P(nodisease) \cdot P(positive | nodisease)}

P(disease) = 0.01% = 0.0001

P(positive disease)  = 99.6% = 0.996

P(nodisease) = (10,000,000 - 100)/10,000,000 = 99.99% = 0.9999

P(positivenodisease) = 0.05% = 0.0005

Whereby 10,000,000 people are tested, 1000 out of the 1,000,000 will have the disease, 1,000 - 0.996 × 1000 = 4 people out of the 1,000 will test negative while 996 will test positive. From the 9,999,000 people who do not have the disease, 9,999,000 × 0.0005 = 4999.5 will give positive test results.

Therefore, the total number of people that tests positive = 4,999.5 + 996 = 5,995.5

Therefore, out of the 5,995.5 that test positive for the disease, 996 will test positive

The probability that someone who tests positive has the genetic disease, P(disease positive) = 996/5,995.5 ≈ 0.166 or 16.6%

Therefore, approximately 16.6% of the people that test positive for the disease actually has the disease

We have;

P(disease | positive) = \dfrac{0.0001 \times 0.996}{0.0001 \times 0.996 + 0.9999 \times 0.0005} = 0.16612459344

8 0
3 years ago
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