This line crosses the point (4,5)so we can make an equation to find the slope:

hope this helps
Answer:
A task time of 177.125s qualify individuals for such training.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
In this problem, we have that:
A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so
.
The fastest 10% are to be given advanced training. What task times qualify individuals for such training?
This is the value of X when Z has a pvalue of 0.90.
Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when
.
So




A task time of 177.125s qualify individuals for such training.
bearing in mind that an infinite geometric sequence, has a limit, namely converges at a value, only if "r" the common factor, is a proper fraction, namely | r | < 1, in this case it's so, thus
![\bf \qquad \qquad \textit{sum of an infinite geometric sequence} \\\\ S=\sum\limits_{i=0}^{\infty}\ a_1 r^{i}\implies S=\cfrac{a_1}{1-r}\quad \begin{cases}a_1=\textit{first term's value}\\ r=\textit{common ratio}\\[-0.5em] \hrulefill\\ a_1=5\\ r=\frac{1}{3} \end{cases} \\\\\\ S=\cfrac{~~5~~}{1-\frac{1}{3}}\implies S=\cfrac{~~5~~}{\frac{2}{3}}\implies S=\cfrac{~~\frac{5}{1}~~}{\frac{2}{3}}\implies S=\cfrac{15}{2}](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Cqquad%20%5Ctextit%7Bsum%20of%20an%20infinite%20geometric%20sequence%7D%20%5C%5C%5C%5C%20S%3D%5Csum%5Climits_%7Bi%3D0%7D%5E%7B%5Cinfty%7D%5C%20a_1%20r%5E%7Bi%7D%5Cimplies%20S%3D%5Ccfrac%7Ba_1%7D%7B1-r%7D%5Cquad%20%5Cbegin%7Bcases%7Da_1%3D%5Ctextit%7Bfirst%20term%27s%20value%7D%5C%5C%20r%3D%5Ctextit%7Bcommon%20ratio%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a_1%3D5%5C%5C%20r%3D%5Cfrac%7B1%7D%7B3%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20S%3D%5Ccfrac%7B~~5~~%7D%7B1-%5Cfrac%7B1%7D%7B3%7D%7D%5Cimplies%20S%3D%5Ccfrac%7B~~5~~%7D%7B%5Cfrac%7B2%7D%7B3%7D%7D%5Cimplies%20S%3D%5Ccfrac%7B~~%5Cfrac%7B5%7D%7B1%7D~~%7D%7B%5Cfrac%7B2%7D%7B3%7D%7D%5Cimplies%20S%3D%5Ccfrac%7B15%7D%7B2%7D)
Answer:
I would help but the picture that's on this question isn't letting me see it so I'll just make a joke....... sorry
if you need help with #2 then you should probably go to a doctor
Answer:
q4. 3/8 chance of landing on even in one spin.
times 120 spins = 45.
Step-by-step explanation:
q5. first option is the answer.