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Snezhnost [94]
3 years ago
13

If an electric kettle uses

Mathematics
1 answer:
cupoosta [38]3 years ago
3 0

Answer:

The energy used in 3.5 hours = 5.25 kilowatts            

Step-by-step explanation:

Energy used by electric kettle:  

  • 2\frac{1}{4}=\frac{9}{4}=2.25 kilowatts

Time taken by electric kettle:

  • 1.5 hours

Electric kettle's rate in kilowatts per hour can be calculated by dividing the spent energy i.e. 2.25 kilowatts by the time taken i.e. 1.5 hours.

Therefore,

Electric kettle's rate = 2.25 kilowatts / 1.5 hour

                                  = 1.5 kilowatts per hour

Thus, the energy used in 3.5 hours = 1.5 × 3.5

                                                           = 5.25 kilowatts

Therefore, the energy used in 3.5 hours = 5.25 kilowatts                        

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SOLVE: 23 (3 + 48) - x =
Damm [24]

Answer: -x + 1173

Step-by-step explanation:

23 (3 + 48) - x

23 x 3 = 69 and 23 x 48 = 1104

(69 + 1104) - x

69 + 1104 = 1173

1173 = -x or -x = 1173

8 0
3 years ago
The cost of your new contact lenses is $200. If you left 25% deposit upon
Contact [7]

Answer: Remaining balance is $150

Step-by-step explanation:

Contact lens= $200

25% of the amount was paid

= 25/100 × 200 = $50

Out of $200 of contact lens, $50 was paid as deposit, subtract $200 from $50 to give balance.

$200 - $50 = $150

I hope this helps.

8 0
3 years ago
The product of c and 7 decreased by 4
svp [43]

Answer:

(c × 7) - 4

Step-by-step explanation:

I hope this helps you, have a nice day! :D

6 0
3 years ago
Read 2 more answers
Write a division expression with a quotient that is: a. greater than 8÷0.001 b. less than 8÷0.001 c. between 8÷0.001 and 8÷ 1 10
VMariaS [17]
9÷0.001 is greater than 8÷0.001.
7÷0.001 is less than 8÷0.001.
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7 0
4 years ago
A 1.0 l buffer solution is 0.15 m in hcn and 0.10 m in nacn. which action will destroy the buffer?
rjkz [21]

The buffer will probably be destroyed by the addition of HCN.

<h3>What is buffer solution?</h3>

A weak acid and the conjugate base of the weak acid, or a weak base and the conjugate acid of the weak base, are combined to form the buffer solution, a water-based solvent solution. They withstand being diluted or having modest amounts of acid or alkali added to them without changing their pH.

Given that a 1.0 l buffer solution is 0.15 m in HCN and 0.10 m in NaCN.

We need to find a action which one destroy the buffer solution.

A buffer is a substance made of salt and a weak acid that is beneficial. From the aforementioned chemicals, HCN is a potent acid and NaCN is a salt between HF and NaCN. Therefore, the buffer will probably be destroyed by the addition of HCN.

To learn more about buffer solution from the given link

brainly.com/question/22390063

#SPJ4

8 0
2 years ago
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