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Paraphin [41]
3 years ago
12

Suppose bob uses the rsa cryptosystem with a very large modulus n for which the factorization cannot be found in a reasonable am

ount of time. suppose alice sends a message to bob by representing each alphabetic character as an integer between 0 and 25 (a s 0, . . . , z s 25), and then encrypting each number separately using rsa with large e and large n. is this method secure? if not, describe the most efficient attack against this encryption method.
Mathematics
1 answer:
Llana [10]3 years ago
3 0

The answer is this method is not secure but a frequency attack can be applied. Knowing the public key in this case is, nonetheless, adequate for an attacker to calculate a table, on behalf of one-to-one communication between the plaintext and the cipher text. Computed table allows him/her to decrypt any ciphertext, encoded using RSA Cryptosystem in such a means.

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At a sale, Salazar bought 4 T-shirts and 3 pairs of jeans for $181. At the same store, Jenna bought 1 T-shirt and 2 pairs of jea
tankabanditka [31]

Answer:

Step-by-step explanation:

4 0
4 years ago
In Texas, 30% of parolees from prison return to prison within 3 years. Suppose 15 prisoners are released from a Texas prison on
LUCKY_DIMON [66]

Answer:

N = 15 ; P = 0.3

Step-by-step explanation:

According to the question, the data provided in the question is as follows

The percentage of parolees from prison return to prison = 30%

Number of years = 3 years

Number of prisoners released from a Texas prision is 15

Based on the above information, the value of the parameters for the binomial random variable X is

N = 15 = number of prisoners

And, the P = Percentage = 30% = 0.3

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3 years ago
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nikklg [1K]

Answer:

B

Step-by-step explanation:

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6 0
3 years ago
Let a = {1, 2, 3, 4, 5} b = {1, 3, 5} c = {4, 6}. find the cardinality of the given set. 33. n(a) 34. n(b) 35. n(a ⋃
bearhunter [10]

1) n(a) = 5


The cardinality of a set is the number of elements in that set. So, you simply need to count how many elements belong to the set, and the answer is 5


2) n(b) = 3


Simlarly, in this case you need to count how many elements belong to the set, the answer is 3


3) n(a ⋃ c) = 6


The union of two set is a set composed by all the elements belonging to either one of the sets, with no repetitions. So, since the first set contains all numbers from 1 to 5, the second set contains a 4, which however already belonged to the first set, but also a 6, which is added in the union. So, a ⋃ c = {1,2,3,4,5,6}, and thus n(a ⋃ c)=6.


4) n(a ⋂ c) = 1


The intersection of two sets is a set composed by the elements belonging to both sets. So, 1,2,3 and 5 don't belong to the intersection, because they belong to the first set alone, while 6 doesn't belong to the intersection because they don't belong to the first one. So, a ⋂ c = {4}, and thus n(a ⋃ c)=1.

4 0
4 years ago
Read 2 more answers
The following table shows the length and width of two rectangles:
faltersainse [42]
The perimeter of these can be found by adding length and width and then multiplying by two. 

Rectangle A: (with all of the variables already doubled)
2x + 16 + 2x - 2 
2x + 2x + 16 - 2
4x + 14
So rectangle A's perimeter is 4x + 14.

Rectangle B: (Still with all the variables already doubled)
8x + 10 + 6x - 4
8x + 6x + 10 - 4
14x + 6
So rectangle B's perimeter is 14x + 6

And now to subtract the two.
(7x + 3) - (4x + 14)
14x + 6 - 4x - 14
14x - 4x + 6 - 14
10x - 8

So it would be C.
5 0
4 years ago
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