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larisa86 [58]
2 years ago
9

Before a baker opened a new sack of flour, the sack weighed 16.25 pounds. After baking all day, the sack weighed 3.8 pounds.

Mathematics
1 answer:
Yuki888 [10]2 years ago
3 0

Answer:

14.25 lb

Explanation:

To get the answer, we need to subtract the final amount of flour at the end of the day from the original amount of flour.

16.25 - 3.80 = 14.25

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Combine the like terms to create an equivalent expression.<br><br> 7k-k+19
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6k +19

Step-by-step explanation:

7k-k+19

Combine like terms

7k-k = 6k

The expression becomes 6k +19

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Kayla saves $110 to purchase a new outfit. She decides to but a skirt for $29.65, a sweater for $38.32, and a purse for $31.00
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Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95
Virty [35]

Answer:

L(x)=1+\dfrac{1}{3}x

\sqrt[3]{0.95} \approx 0.9833

\sqrt[3]{1.1} \approx 1.0333

Step-by-step explanation:

Given the function: g(x)=\sqrt[3]{1+x}

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial,L(x)=f(a)+f'(a)(x-a)

a=0

g(0)=\sqrt[3]{1+0}=1

g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}

Therefore:

L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x

(b)\sqrt[3]{0.95}= \sqrt[3]{1-0.05}

When x = - 0.05

L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833

\sqrt[3]{0.95} \approx 0.9833

(c)

(b)\sqrt[3]{1.1}= \sqrt[3]{1+0.1}

When x = 0.1

L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333

\sqrt[3]{1.1} \approx 1.0333

7 0
3 years ago
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