All categories

2 years ago

Help will make you as brain

Mathematics

2 answers:

andre [41]2 years ago

8 0

Annnnsssswwweeeerrrrr:33333

Nooooo

Tomtit [17]2 years ago

7 0

Answer:

you still cant see it

Step-by-step explanation:

You might be interested in

32% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a

Tems11 [23]

Answer:

a) $P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

b) $P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668$

c) $P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816$

Step-by-step explanation:

1) Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

2) Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=10, p=0.32)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

$P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

Part b

$P(X> 2)=1-P(X\leq 2)=1-[P(X=0)+P(X=1)+P(X=2)]$

$P(X=0)=(10C0)(0.32)^0 (1-0.32)^{10-0}=0.0211$

$P(X=1)=(10C1)(0.32)^1 (1-0.32)^{10-1}=0.0995$

$P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

$P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668$

Part c

$P(2 \leq x \leq 5)=P(X=2)+P(X=3)+P(X=4)+P(X=5)$

$P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211$

$P(X=3)=(10C3)(0.32)^3 (1-0.32)^{10-3}=0.264$

$P(X=4)=(10C4)(0.32)^4 (1-0.32)^{10-4}=0.218$

$P(X=5)=(10C5)(0.32)^5 (1-0.32)^{10-5}=0.123$

$P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816$

6 0

3 years ago

A gallon of moo milk cost 5.12 what is the price in dollars of an 8

Travka [436]

I am confused on what the question is.

7 0

3 years ago

What is the value of 9905482

Vladimir79 [104]

9= 9,000,000/ nine million
9= 900,000/ nine hundred thousand
0= since there's no value we leave it out.
5= 5000/ five thousand
4= 400/ four hundred
8= 80/ eighty
2= 2/two
So your answer is:
Nine million nine hundred thousand five thousand four hundred and eighty two.

3 0

3 years ago

How much will it cost to print a circular sign with a radius of 1.1 feet if the printing company charges $27 per square foot? us

Serga [27]

Answer: To find the cost to print a circular frame, we need to first find the area of circle.

Given: $r=1.1$

We know that:

Area of circle $=\pi \times r^{2}$

$=3.14 \times 1.1^{2}$

$=3.7994$

Also we are given cost per square foot is $27

Therefore, the cost to print a circular sign with a radius of 1.1 feet is:

$3.7994 \times 27= 102.58$ or $102.58

3 0

3 years ago

The demand function for a product is modeled by p = 400 − 4x, 0 ≤ x ≤ 100, where p is the price per unit (in dollars) and x is t

lawyer [7]

Answer:

Demand is Elastic when Price > 200 ; Demand is inelastic when Price < 200

Step-by-step explanation:

p = 400 - 4x

4x = 400 - p

x = (400 - p) / 4 → x = 100 - p/4

Elasticity of demand [ P ed ] = (Δx / Δp) x (p / x)

Δx / Δp [Differentiating x w.r.t p] = 0 - 1/4 → = -1/4

P ed = -1 x p

4 (400 - p)/4

= -1 x 4p = -p / (400-p)

4 (400 - p)

Price Elasticity of demand : only magnitude is considered, negative sign is ignored (due to negative price demand relationship as per law of demand).

So, Ped = p / (400 - p)

Demand is Elastic when P.ed > 1

p / (400-p) > 1

p > 400 - p

p + p > 400 → 2p > 400

p > 400 / 2 → p > 200

Demand is inelastic when P.ed < 1

p / (400-p) < 1

p < 400 - p

p + p < 400 → 2p < 400

p < 400 / 2 → p < 200

4 0

3 years ago