The function j(x)=39x is the number of jumping jacks you can do in x minutes how many can you do in 5 minutes'?
This is asking you to evaluate the function when x is 5...so all you do here is substitute 5 for x and simplify.. since the question defines "x" as the number of minutes...and j(x) represents the number of jumping jacks.
j(x) = 39x
j(5) = 39(5)
j(5) = 195 <--- answer...
So you do 195 jumping jacks in 5 minutes
I really hope this helps :)
Answer:
y = 0
Step-by-step explanation:
A parallelogram is a quadrilateral with opposite sides parallel. Then segment CD must be parallel to AB, and CB must be parallel to DA. Two different segments are parallel if they have the same slope.
slope of DA = (yA - yD)/(xA - xD) = (4 - 2)/(1 - (-1)) = 1
slope of CB = (yB - yC)/(xB - xC) = (2 - yC)/(1 - (-1)) = 1
(2 - yC) = 2 * 1
2 - 2 = yC
0 = yC
Note: coordinates of A are (xA, yA), of B are (xB, yB), of C are (xC, yC) and of D are (xD, yD)
19) 67x²+115x+48
20) (w+8)²
21) (d+11)²
22) (r+7)(r-7)
Explanation:
19) The area of the ceiling is given by (10x+9)(7x+7). Multiplying we have:
10x*7x+7*10x+9*7x+9*7
=70x²+70x+63x+63
=70x²+133x+63
The area of the skylight is given by (x+5)(3x+3). Multiplying we have:
x*3x+3*x+5*3x+5*3
=3x²+3x+15x+15
=3x²+18x+15
To find the remaining area of the ceiling we subtract:
(70x²+133x+63)-(3x²+18x+15)
=70x²+133x+63-3x²-18x-15
=67x²+115x+48
20) To factor, we want to find factors of c, 64, that sum to b, 16. 8*8=64 and 8+8=16; therefore we have:
(w+8)(w+8)
Since this is the same binomial twice, we write it as (w+8)²
21) Again we look for factors of c, 121, that sum to b, 22. 11*11=121 and 11+11=22, so:
(d+11)(d+11)
Since this is the same binomial twice, we have (d+11)²
22) Factors of -49 that sum to 0 (there is no r term, just r²): -7*7=-49 and -7+7=0, so:
(r-7)(r+7)
There are two different lines
