Ask question

Ask question

All categories

2 years ago

6

A group of 29 friends get together to play a sport first person must be divided into team each team has to have exactly 4 player

s and no one can on a team more than once. How many team can they make

1 answer:

telo118 [61]2 years ago

5 0

Answer:

7 teams remaining a person

Step-by-step explanation:

29/4 = 7 remainder 1

You might be interested in

borishaifa [10]

Answer:

umm idk let me get back to you

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Solve Highschool Pre cal

Bezzdna [24]

Option C:

$\ln 64 y^{2}$

Solution:

Given expression: 2 ln 8 + 2 ln y

Applying log rule $a \log b=\log b^{a}$ in the above expression.

⇒ $2 \ln 8+2 \ln y=\ln 8^{2}+\ln y^{2}$

Applying log rule $\log a+\log b=\log (a b)$ in the above expression.

⇒ $\ln 8^{2}+\ln y^{2}=\ln \left(8^{2} y^{2}\right)$

We know that $8^{2}=64$

⇒ $\ln \left(8^{2} y^{2}\right)=\ln 64 y^{2}$

Hence, the expression in single natural logarithm is $\ln 64 y^{2}$ .

6 0

2 years ago

2-x-3 combining like terms please

Olenka [21]

Answer: -1x - 1

Step-by-step explanation:

2 -1x -3

2-3 = -1

-1x - 1

4 0

2 years ago

Properties of exponents<br> Rewrite the expression in the form b^n—— (b^2)^3/7

exis [7]

Answer:

$b^{\frac{6}{7}}$ is the required expression.

Step-by-step explanation:

$(b^2)^{\frac{3}{7}}\\\\\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0\\\\=b^{2\cdot \frac{3}{7}}\\\\=b^{\frac{6}{7}}$

Best Regards!

3 0

2 years ago

Solve the following equation for I. A = 2nr + nrl. Explain each step please

Cloud [144]

Sorry I’m not sure but I’ll try and help- lemme just add it to a different comment

3 0

2 years ago