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Shkiper50 [21]
2 years ago
15

What pair of number is relatively prime 7 and 21 or 4 and 15 or 6 and 9 or 9 and 27

Mathematics
1 answer:
Molodets [167]2 years ago
7 0
Since, 3 is the common factor in Factorization of both the numbers, therefore they are not prime numbers. The relative prime pair is 16 and 39.
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What is the equation of the line that passes through the point (-4,3) and has a slope of –5/4​
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Step-by-step explanequation of line passing through (x₁,y₁):-

y-y₁=m(x-x₁)

The equation of line which passes through (4,3) and slope is 5/4

y-3=5/4(x-4)

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The perimeter of a rectangular parking lot is 296 m if the width of the parking lot is 65 m , what is its length
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166

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Find the surface area of this triangular prism. Be sure to include the correct unit in your answer.
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4 0
3 years ago
Given the circle with the equation (x - 3)2 + y2 = 49, determine the location of each point with respect to the graph of the cir
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To find out if a point is inside, on, or outside a circle, we need to substitute the ordered pair into the equation of the circle:
(x-xc)^2+(y-yc)^2=r^2
where (xc,yc) is the centre of the circle, and r=radius of the circle.

If the left-hand side [(x-xc)^2+(y-yc)^2] is less than r^2, then point (x,y) is INSIDE the circle.  If the left-hand side is equal to r^2, the point is ON the circle.
Finally, if the left-hand side is greater than r^2, the point is OUTSIDE the circle.

For the given problem, we have xc=3, yc=0, or centre at (3,0), r=sqrt(49)=7
(x-xc)^2+(y-yc)^2=r^2 => (x-3)^2+y^2=7^2

A. (-1,1), 
(x-3)^2+y^2=7^2 => (-1-3)^2+1^2=16+1=17 <49  [inside circle]

B. (10,0)
(x-3)^2+y^2=7^2 => (10-3)^2+0^2=49+0=49  [on circle]

C. (4,-8)
(x-3)^2+y^2=7^2 => (4-3)^2+(-8)^2=1+64=65 > 49  [outside circle]


5 0
2 years ago
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