PLEASE HELP MEE!! IVE BEEN DOING THIS ASSIGNMENT FOR OVER 2 HOURS NOW, PLS HELP.. :(
2 answers:
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First, we are going to find the radius of the yaw mark. To do that we are going to use the formula: 
where
is the length of the chord
is the middle ordinate
We know from our problem that the tires leave a yaw mark with a 52 foot chord and a middle ornate of 6 feet, so
and 
. Lets replace those values in our formula:
Next, to find the minimum speed, we are going to use the formula:
where
is <span>drag factor
</span>
is the radius
We know form our problem that the drag factor is 0.2, so
. We also know from our previous calculation that the radius is 
, so 
. Lets replace those values in our formula:
mph
We can conclude that Mrs. Beluga's minimum speed before she applied the brakes was 13.34 miles per hour.
where
We know from our problem that the tires leave a yaw mark with a 52 foot chord and a middle ornate of 6 feet, so
Next, to find the minimum speed, we are going to use the formula:
where
</span>
We know form our problem that the drag factor is 0.2, so
We can conclude that Mrs. Beluga's minimum speed before she applied the brakes was 13.34 miles per hour.
Given:
Line a is perpendicular to line b .
Line a passes through the points (1,-8) and (9,-12) .
Line b passes through the point (-8, -16).
To find:
The equation of b.
Solution:
Line a passes through the points (1,-8) and (9,-12) . So, slope of line a is
Product of slopes of two perpendicular lines is -1.
Slope of line b is 2.
If a line passing through a point with slope m, then equation of line is
Line b passing through (-8,-16) with slope 2. So, equation of line b is
Subtract 16 from both sides.
Therefore, the equation of line b is .