All categories

3 years ago

Help please. A) 60 B)120 C)140

Mathematics

1 answer:

kvasek [131]3 years ago

8 0

Hi there,

The answer to your question is:

B. 120

Hope this helped,

Sincerely,

Dus4nR

You might be interested in

Can someone please help

Masteriza [31]

19 hours is your answer

8 0

3 years ago

Read 2 more answers

Find tan theta if theta is an angle in standard position and the point with coordinates (4,3) lies on the terminal side of the a

Karolina [17]

Answer: 0.75

Step-by-step explanation:

We can do this by drawing a terminal side in a standard position and then drawing the associated triangle. We then use the Pythagoras theorem to find the missing side the hypotenuse. Then, this will give a Pythagorean Triplet of 3, 4 and 5.

We now have a triangle with the values of:

x = 4

y =3

h^2= 4^2 + 3^2

h^2 = 16 + 9

h^2 = 25

h = 5

Tangent = opposite/adjacent

= y/x

= 3/4

= 0.75

8 0

3 years ago

Ahhhh i need help again.

qwelly [4]

Answer:

Step-by-step explanation:

A. these simply to 21 + 7x and 21 + 3x

this one is incorrect because the 7x and 3x are different

B. these simplify to 10 + x and 10 + x

this is the correct one since they are exactly the same

C. these simplify to 21x and 7x + 21

these two are not the same because one expression has only a number with a variable but the other one has a number with a variable <em>and </em>another number

D. these simplify to $\frac{7}{3-x}$ and $\frac{7}{x-3}$

in subtraction, the order of the 3 and the x matters, so the equations are not the same
example: 6 - 4 = 2 but 4 - 6 = -2

3 0

3 years ago

I need help I don’t get it plz help

makkiz [27]

D because it would 44 below since 4 times 7 = 28 so it would switch over for to 6 times 7 =44

4 0

3 years ago

Read 2 more answers

If a cup of coffee has temperature 97Â°C in a room where the ambient air temperature is 25Â°C, then, according to Newton's Law o

FinnZ [79.3K]

Answer:

The average temperature is $T_{a} = 81.95^oC$

Step-by-step explanation:

From the question we are told that

The temperature of the coffee after time t is $T(t) = 25 + 72 e^{[-\frac{t}{45} ]}$

Now the average temperature during the first 22 minutes i.e fro $0 \to 22$ minutes is mathematically evaluated as

$T_{a} = \frac{1}{22-0} \int\limits^{22}_{0} {25 +72 e^{[-\frac{t}{45} ]}} \, dx$

$T_{a} = \frac{1}{22} [25 t + 72 [\frac{e^{[-\frac{t}{45} ]}}{-\frac{1}{45} } ] ] \left| 22} \atop {0}} \right.$

$T_{a} = \frac{1}{22} [25 t - 3240e^{[-\frac{t}{45} ]} ] \left | 45} \atop {{0}} \right.$

$T_{a} = \frac{1}{22} [25 (22) - 3240e^{[-\frac{22}{45} ]} - (- 3240e^{0} )]$

$T_{a} = \frac{1}{22} [550 - 1987.12 + 3240]$

$T_{a} = 81.95^oC$

8 0

3 years ago