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3 years ago

Help and explain please! 2x+3y=12 Solve for y.

Mathematics

1 answer:

kenny6666 [7]3 years ago

4 0

your question: 

Help and explain please!

Help and explain please! 2x+3y=12

Help and explain please! 2x+3y=12Solve for y.

answer: 

2x + 3y = 12

so basically we want to get y by its self.

first were going to get y on the left side and everything else on the right. in order to do that we have to subtract 2x from the left and do the same on the other side.

2x + 3y=12

-2x. -2x

3y = 12 -2x

then we divide everything by 3 on the other side to get y by its self.

3y = 12-2x

--- ----. ----

3. 3. 3

y= 4 -2/3x

should be your answer.

Hope this helps, have a great day!

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The perimeter of a quadrilateral (four-sides polygon) is 50 inches. The longest side is three times as long as the shortest side

kkurt [141]

The side lengths of quadrilateral are 21 inches; 11 inches; 11 inches; 7 inches.

SOLUTION:

Given, the perimeter of a quadrilateral (four-side polygon) is 50 inches.

Let the length of shortest side be n inches. The longest side is three times as long as the shortest side.

That is, length of largest side = 3n inches

The other two sides are equally long and are 4 inches longer than the shortest side.

Then, length of remaining two sides = 4 + n inches

We have to find the length of all four sides.

Now, we know that, perimeter = 50 inches

$\begin{array}{l}{\rightarrow \text { Sum of all sides }=50} \\\\ {\rightarrow n+3 n+n+4+n+4=50} \\\\ {\rightarrow n+3 n+n+n=50-4-4} \\\\ {\rightarrow 6 n=42} \\\\ {\rightarrow n=7}\end{array}$

So, length of sides will be,

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