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Sedaia [141]
3 years ago
14

Which term is defined as a push or a pull?

Physics
2 answers:
erastovalidia [21]3 years ago
6 0

Answer:

A force is a push or pull upon an object resulting from the object's interaction with another object.

Frictional Force: Gravitational Force

Normal Force: Magnetic Force

Tension Force: Electrical Force

Contact Forces: Action-at-a-Distance Forces

Explanation:

weqwewe [10]3 years ago
4 0

Answer:

I hope it helps you :)

Explanation:

A force is a push or pull upon an object resulting from the object's interaction with another object.

Frictional Force: Gravitational Force

Tension Force: Electrical Force

Normal Force: Magnetic Force

Contact Forces: Action-at-a-Distance Forces

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In a pool with the width of 50 m Tony swims down and back in 30 s. What is his average speed?
marshall27 [118]

Answer:

3.3 m/s

Explanation:

8 0
3 years ago
A man with mass 82 kg runs at a speed of 2.8 ms How much kinetic energy does he have?? A.114.8 B.221.8 C.321.4 D.642.9
Delvig [45]
Use the formula for kinetic energy.
KE=1/2mv^2
KE=1/2*(82kg)*(2.8m/s)^2
KE=321.4 J
The answer is C
3 0
3 years ago
Alberto is walking east at 10 m/s from his house to his grandma's house. It takes him 30s to walk 50 m/s more to his grandma's h
Pachacha [2.7K]

Answer:

Acceleration = 1.33m/s² East

Explanation:

Given the following data;

Initial velocity = 10m/s

Final velocity = 50m/s

Time = 30secs

To find the acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

a = \frac{v  -  u}{t}

Where,

a is acceleration measured in ms^{-2}

v and u is final and initial velocity respectively, measured in ms^{-1}

t is time measured in seconds.

Substituting into the equation, we have;

a = \frac{50 - 10}{30}

a = \frac{40}{30}

Acceleration = 1.33m/s² East

3 0
3 years ago
1. A heat engine operates between two reservoirs at T2 = 600 K and T1 = 350 K. It takes in 1.00 x 103 J of energy from the highe
Alex73 [517]

Answer:

\Delta S_u=2.1429\ J.K^{-1}

W_c=416.67\ J

Explanation:

Given:

temperature of source reservoir, T_H=600\ K

temperature of sink reservoir, T_L=350\ K

energy absorbed from the source, Q_{in}=1000\ J

work done, W=250\ J

a.

<u>Now change in entropy of the surrounding:</u>

\Delta S_u=\frac{dQ_L}{T_L}

<em>Since heat engine is a device that absorbs heat from a high temperature reservoir and does some work giving out heat in the universe as the byproduct.</em>

\Delta S_u=\frac{Q_H-W}{T_L}

\Delta S_u=\frac{1000-250}{350}

\Delta S_u=2.1429\ J.K^{-1}

b.

<u>We know Carnot efficiency is given as:</u>

\eta_c=1-\frac{T_L}{T_H}

\eta_c=1-\frac{350}{600}

\eta_c=0.4167

<u>Now the Carnot work done:</u>

W_c=Q_H\times \eta_c

W_c=1000\times 0.4167

W_c=416.67\ J .......................(1)

c.

From eq. (1) we have the Carnot work, so the difference:

\Delta W=W_c-W

\Delta W=416.67-250

\Delta W=166.67\ J

Now, we find:

T_L.\Delta S_u=350\times 2.1429

5 0
3 years ago
Heyi can u answer this matey??
Rudik [331]
It is true my dude.
7 0
3 years ago
Read 2 more answers
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