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faust18 [17]
3 years ago
15

You push a disk-shaped platform tangentially on its edge 2.0 m from the axle. The platform starts at rest and has a rotational a

cceleration of 0.30 rad/s2. Determine the distance you must run while pushing the platform to increase its speed at the edge to 7.0 m/s.
Physics
1 answer:
Natali [406]3 years ago
7 0

Answer: 40.84 m

Explanation:

Given

Radius of the disk, r = 2m

Velocity of the disk, v = 7 rad/s

Acceleration of the disk, α = 0.3 rad/s²

Here, we use the formula for kinematics of rotational motion to solve

2α(θ - θ•) = ω² - ω•²

Where,

ω• = 0

ω = v/r = 7/2

ω = 3.5 rad/s

2 * 0.3(θ - θ•) = 3.5² - 0

0.6(θ - θ•) = 12.25

(θ - θ•) = 12.25 / 0.6

(θ - θ•) = 20.42 rad

Since we have both the angle and it's radius, we can calculate the arc length

s = rθ = 2 * 20.42

s = 40.84 m

Thus, the needed distance is 40.84 m

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sergiy2304 [10]

Answer:

10 cm

Explanation:

water depth had the biggest difference in survival rates for embryos with UV-B protection versus embryos without UV-B protection is 10 cm . the bar graph attached in the shows that the lengths of yellow and brown bars differ the most at 10 cm.

Hence,The biggest difference between the survival rates of UV-B protected and unprotected can be seen at the depth of 10 cm.

6 0
3 years ago
A 4kg block slides freely across a rough surface such that the block slows down with an acceleration of −1.25 m/s2 . What is the
Sophie [7]

Answer:

The coefficient of kinetic friction between the block and the surface is 0.127.

Explanation:

Given that,

The mass of a block, m = 4 kg

The acceleration of the block, a = -1.25 m/s²

We need to find the coefficient of kinetic friction between the block and the surface. The force of friction is given by :

F=\mu mg\\\\ma=\mu mg\\\\\mu=\dfrac{a}{g}\\\\\mu=\dfrac{1.25}{9.8}\\\\\mu=0.127

So, the coefficient of kinetic friction between the block and the surface is 0.127.

6 0
3 years ago
Are molecular compounds and covalent molecules the same thing ?
likoan [24]
Yes, they are synonymous terms.
5 0
3 years ago
What do psychologists used to assist them in diagnosing abnormal behavior?
soldier1979 [14.2K]

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8 0
3 years ago
a car accelerates uniformly from rest to a speed of 65 km/h (18 m/s) in 12s. Find the distance the car travels during this time?
Vinil7 [7]

The car's speed was zero at the beginning of the 12 seconds,
and 18 m/s at the end of it.  Since the acceleration was 'uniform'
during that time, the car's average speed was (1/2)(0 + 18) = 9 m/s.

12 seconds at an average speed of 9 m/s  ==>  (12 x 9) = 108 meters .

==========================================

That's the way I like to brain it out.  If you prefer to use the formula,
the first problem you run into is:  You need to remember the formula !

The formula is        D = 1/2 a T²

                   Distance = (1/2 acceleration) x (time in seconds)²

             Acceleration = (change in speed) / (time for the change)
                                  =        (18 m/s)            /        (12 sec)
                                  =                      1.5 m/s² .

                  Distance  =  (1/2 x 1.5 m/s²) x (12 sec)²
                                  =       (0.75 m/s²)  x  (144 sec²)  =  108 meters .

5 0
4 years ago
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