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AysviL [449]
3 years ago
9

Heat is transferred at a rate of 2 kW from a hot reservoir at 800 K to a cold reservoir at 300 K. Calculate the rate at which th

e entropy of the two reservoirs changes and determine if the second law is satisfied
Physics
1 answer:
vekshin13 years ago
6 0

Answer:

0.00417 kW/K or 4.17 W/K

Second law is satisfied.

Explanation:

Parameters given:

Rate of heat transfer, Q = 2kW

Temperature of hot reservoir, Th = 800K

Temperature of cold reservoir, Tc = 300K

The rate of entropy change is given as:

ΔS = Q * [(1/Tc) - (1/Th)]

ΔS = 2 * (1/300 - 1/800)

ΔS = 2 * 0.002085

ΔS = 0.00417 kW/K or 4.17 W/K

Since ΔS is greater than 0, te the second law of thermodynamics is satisfied.

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son4ous [18]

Answer:

The answer is 13 however make sure if they ask for a certain measurement like meter answer it by saying 13 meters.

Explanation:

This basically turns into basic algebra if you know the formula for work. The formula for work is W=F*d  

Here are the variables that you know 650J=50N*d so you need d.

All you do is divide 650J by 50N and you get a total of 13 (meters since I don't know what they want you to put it in).

6 0
3 years ago
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Explanation:

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2 years ago
The two waves shown below pass through the same medium in the phases shown and interfere with each other.
ale4655 [162]

A. W

Explanation:

The wave that would be produced by the interaction of the two waves shown in the diagram is wave W.

There is no wave in the diagram W.

This type of interference is known as destructive interference.

  • Destructive interference occurs when two waves out of phase comes together.
  • In this way, they cancel out each other and are terminated.
  • If the two waves are in phase, they will reinforce one another.
  • When waves reinforce one another, a constructive interference has occurred.

learn more:

Color in soap bubbles brainly.com/question/8733443

#learnwithBrainly

5 0
3 years ago
Read 2 more answers
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jarptica [38.1K]
I think everything looks good but 2 might not be right, it might be B
5 0
3 years ago
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a ball is projected horizontally with a velocity of 5 m per second from the top of a building 19.6 m high how long will the ball
zepelin [54]

Answer:

1.98s

Explanation:

The time taken to hit the ground is given by

h=ut+ 1/2 at^2

but u =0

so we have

h=1/2at^2

making t the subject

t=√2h/g

√2×19.6/10

1.98s

8 0
2 years ago
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