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snow_tiger [21]
3 years ago
10

(4x-y=-15)(3x-2y=-10)​

Mathematics
1 answer:
Andreyy893 years ago
5 0

Answer:

<h2>x = -4 and y = -1 → (-4, -1)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}4x-y=-15&\text{multiply both sides by (-2)}\\3x-2y=-10\end{array}\right\\\underline{+\left\{\begin{array}{ccc}-8x+2y=30\\3x-2y=-10\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad-5x=20\qquad\text{divide both sides by (-5)}\\.\qquad\qquad\boxed{x=-4}\\\\\\\text{Put the value of x to the first equation.}\\\\4(-4)-y=-15\\-16-y=-15\qquad\text{add 16 to both sides}\\-y=1\qquad\text{change the signs}\\\boxed{y=-1}

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Step-by-step explanation:

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Read 2 more answers
Working alone Ryan can dig a 10ft by 10ft hole in five hours castel can dig the same same hole in six how long would it take the
Sergeeva-Olga [200]

Answer:

The time taken by both when they work together is 2 hours 42 minutes .

Step-by-step explanation:

Given as :

The time taken by Ryan to dig 10 ft by 10 ft hole = x = 5 hours

The time taken bu Castel to dig 10 ft by 10 ft hole = y = 6 hours

Let The time taken by both when they work together = z hours

<u>According to question</u>

The time taken by both when they work together = time taken by Ryan to dig 10 ft by 10 ft hole + time taken bu Castel to dig 10 ft by 10 ft hole

i.e \dfrac{1}{z} = \dfrac{1}{x} + \dfrac{1}{y}

Or,  \dfrac{1}{z} = \dfrac{1}{5}  +  \dfrac{1}{6}

<u>Taking LCM</u>

Or,  \dfrac{1}{z} = \dfrac{6 + 5}{30}

Or,  \dfrac{1}{z} = \dfrac{11}{30}

Or, z = \dfrac{30}{11}   hours

∴  z = 2 hours 42 minutes

So, The time taken by both when they work together = z = 2 hours 42 min

Hence, The time taken by both when they work together is 2 hours 42 minutes . Answer

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3 years ago
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