Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S and q is _____ the force exerted between S and p
a. 1/2
b. 2 times
c. 1/4
d. 4 times
Answer:
4 times
Step-by-step explanation:
Given the following :
Distance between q and S (r) = 1 unit
Distance between P and S (r) = 2 × 1 unit = 2
According to coliumbs law:
F = Ke(q1q2) /r^2
Where F = electrostatic force, Ke = coloumbs constant
q1,q2 = charges, r = distance between two charges
For q and S :
Fsq = Ke(q1q2) / 1^2
Fsq = Ke(q1q2) - - - - - equation 1
For P and S :
Fsp = Ke(q1q2) / 2^2
Fsp = Ke(q1q2) / 4 - - - - - equation 2
Dibiding equation 1 by equation 2
Fsq/Fsp = Ke(q1q2) / Ke(q1q2)/4
Fsq / Fsp = Ke(q1q2) × 4 / Ke(q1q2)
Fsq / Fsp = 4 / 1
Using cross multiplication
Therefore, Fsq = 4 × Fsp
Answer:
Step-by-step explanation:
Given that there are two functions f and g as
We have to find the composition of functions.
Composition functions are calculated as the first function inside bracket and then the outside function of answer inside.
a)
b)
c)
d)
Answer: The most typical system you will find is a system of linear equations. And frequently, you will find systems of equations that are linear, with two equations and two unknowns. These systems are usually call 2x2 system of linear equations.
Step-by-step explanation:
13. Minus 4
14. Minus 200
15. Minus 30