equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4)
Perpendicular bisector lies at the midpoint of a line
Lets find mid point of (-9,-8) and (7,-4)
midpoint formula is


midpoint is (-1, -6)
Now find the slope of the given line
(-9,-8) and (7,-4)


Slope of perpendicular line is negative reciprocal of slope of given line
So slope of perpendicular line is -4
slope = -4 and midpoint is (-1,-6)
y - y1 = m(x-x1)
y - (-6) = -4(x-(-1))
y + 6 = -4(x+1)
y + 6 = -4x -4
Subtract 6 on both sides
y = -4x -4-6
y= -4x -10
equation for the perpendicular Bisector y = -4x - 10
I believe the 3rd answer down if the information you provided is correct
Squaring the sum on the top, rules out 1 and 2 (not squaring the 7 only)
then 4 times the difference. so I believe 4 (x-1) on the bottom.
we know that
<u>a) By corresponding angles</u>
m∠6=m∠2
<u>b) By vertical angles</u>
m∠6=
so
m∠2=
--------> equation 
<u>c) By supplementary angles</u>
+m∠2=
--------> equation 
substitute equation
in equation 




<u>Find m∠6 </u>
m∠6=
m∠6=
therefore
<u>the answer is</u>
the measure of the angle 6 is
Answer:
The answer is -7.15, hope this helps.
S=4P+4Q
S=4(P+Q)
S/4=P+Q
S/4-P=Q
Q=S/4-P