Answer:
0.7698
Step-by-step explanation:
If you call your random variable 
, then what you are looking for is
because you want the probability of being <em>between 87 and 123.</em>
We need a table with of the normal distribution. But we can only find the table with 
and 
. Because of that, first we need to <em>normalize </em>our random variable:
(you can always normalize your variable following the same formula!)
now we can do something similar to our limits, to get a better expression:
And we transform our problem to a simpler one:
(see Figure 1)
From our table we can see that 
(this is represented in figure 2).
Remember that the whole area below the curve is exactly 1. So we can conclude that 
(because 0.8849 + 0.1151 = 1). We also know the normal distribution is symmetric, then
.
FINALLY:
<u>Answer: </u>
Sum of the roots of the polynomial 
<u>Solution:</u>
The general form of cubic polynomial is 
---- (1)
If we have any cubic polynomial having roots 
Sum of roots 
= 
---(2)
From question given that,
--- (3)
On comparing equation (1) and (3), we get a = 1, b = 2, c = -11 and d = -12
Hence the sum of roots using eqn 2 is given as,
= 
= -2
Hence the sum of the roots of the polynomial
I can’t really graph on this but place a dot on the four on the y axis and go up one and over two and place a dot there. just keep repeating it till u get to the end of the graph :)
The total was $29.
1. Write an equation. 24+(2.50*2)= x
2. Solve your equation using PEMDAS
*2.5*2=5
*5+24=
3. Simplify equation.
5+24=29
Given:
<span>11 11.5 10.5 17 14.5 14.5 18 17 19
Arrange in chronological order from least to greatest.
10.5 ; 11 ; 11.5 ; 14.5 ; 14.5 ; 17 ; 17 ; 18 ; 19
</span><span>I used an online lower and upper fence calculator to get the necessary data.
Minimum: 10.5
Maximum: 19
Q1: 11.25
Q2 or median: 14.5
Q3: 17.5
Interquartile range can be solved by subtracting the value of Q1 from the value of Q3
IQR = Q3 - Q1
IQR = 17.5 - 11.25
IQR = 6.25 CHOICE A. </span>
