1885.5 m^3 of water will fill the container.
To find how many cubic feet of water will it contain:
Given -
- Lauren has an above-ground swimming pool.
- The water level in the pool must be 4 inches above the pool's surface in order for the skimmer to function properly.
- π = 3.14
The pool comprises a 12-foot-radius cylinder with a height of 4.5 feet.
- Height of pool = 4.5 ft
- Radius of pool = 12 ft
- The height of the water is 4 inches below the pool top
- 12 inches make 1 ft
- 4 inches = 4/12 ft = 0.33 ft
- Therefore, height of water = 4.5 - 0.33 = 4.17 ft
The volume of the water in this section of the cylinder will be equal to the volume of the cylinder formed.
- The volume of the cylinder formed by the water = volume of water =
![\pi r^{2} h](https://tex.z-dn.net/?f=%5Cpi%20r%5E%7B2%7D%20h)
- volume = 3.14 x
x 4.17 = 1885.5 m^3 of water
Therefore, 1885.5 m^3 of water will fill the container.
Know more about volumes here:
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The complete question is given below:
Lauren has an above-ground pool. To keep the pool's skimmer working well, the water level must be 4 inches from the top of the pool. When the pool is filled to this recommended level, approximately how many cubic feet of water will it contain? Use π = 3.14
A cylinder with a radius of 12 feet and a height of 4.5 feet.
Answer:
x = 53
Step-by-step explanation:
The sum of the angle measures in a triangle is 180°:
91° + 36° + x° = 180°
x° = 180° -127° = 53°
x = 53
The probability that it rains at most 2 days is 0.00005995233 and the variance is 0.516
<h3>The probability that it rains at most 2 days</h3>
The given parameters are:
- Number of days, n = 7
- Probability that it rains, p = 95%
- Number of days it rains, x = 2 (at most)
The probability that it rains at most 2 days is represented as:
P(x ≤ 2) = P(0) + P(1) + P(2)
Each probability is calculated as:
![P(x) = ^nC_x * p^x * (1 - p)^{n - x}](https://tex.z-dn.net/?f=P%28x%29%20%3D%20%5EnC_x%20%2A%20p%5Ex%20%2A%20%281%20-%20p%29%5E%7Bn%20-%20x%7D)
So, we have:
![P(0) = ^7C_0 * (92\%)^0 * (1 - 92\%)^{7 - 0} = 0.00000002097](https://tex.z-dn.net/?f=P%280%29%20%3D%20%5E7C_0%20%2A%20%2892%5C%25%29%5E0%20%2A%20%281%20-%2092%5C%25%29%5E%7B7%20-%200%7D%20%3D%200.00000002097)
![P(1) = ^7C_1 * (92\%)^1 * (1 - 92\%)^{7 - 1} = 0.00000168821](https://tex.z-dn.net/?f=P%281%29%20%3D%20%5E7C_1%20%2A%20%2892%5C%25%29%5E1%20%2A%20%281%20-%2092%5C%25%29%5E%7B7%20-%201%7D%20%3D%200.00000168821)
![P(2) = ^7C_2 * (92\%)^2 * (1 - 92\%)^{7 - 2} = 0.00005824315](https://tex.z-dn.net/?f=P%282%29%20%3D%20%5E7C_2%20%2A%20%2892%5C%25%29%5E2%20%2A%20%281%20-%2092%5C%25%29%5E%7B7%20-%202%7D%20%3D%200.00005824315)
So, we have:
P(x ≤ 2) =0.00000002097 + 0.00000168821 + 0.00005824315
P(x ≤ 2) = 0.00005995233
Hence, the probability that it rains at most 2 days is 0.00005995233
<h3>The mean</h3>
This is calculated as:
Mean = np
So, we have:
Mean = 7 * 92%
Evaluate
Mean = 6.44
Hence, the mean is 6.44
<h3>The standard deviation</h3>
This is calculated as:
σ = √np(1 - p)
So, we have:
σ = √7 * 92%(1 - 92%)
Evaluate
σ = 0.718
Hence, the standard deviation is 0.718
<h3>The variance</h3>
We have:
σ = 0.718
Square both sides
σ² = 0.718²
Evaluate
σ² = 0.516
This represents the variance
Hence, the variance is 0.516
Read more about normal distribution at:
brainly.com/question/4079902
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I guess the question is incomplete...