Answer:
Option A, 
Step-by-step explanation:
Given: Deborah bought a computer for 
off the list price.
The list price is 
.
To find: The amount Deborah spent on the computer.
Solution: We have,
List price of the computer 
.
Deborah bought the computer for off the list price.
The amount Deborah spent on the computer 
.
So, Deborah spent on the computer.
Hence, option A is correct.
Answer: 7°
Explanation:
FBD = EBC
2x + 3 = 9x - 11
-7x = -14
x = -14/-7
x = 2
EBC = 9(2) - 11 = 18 - 11 = 7°
Answer:
14 square units
Step-by-step explanation:
There are several ways we can find the area. Probably the easiest is to cut the kite in half vertically and find the area of each triangle. The area of the kite will be double that.
The height of the kite is 7 units, and the width is 4 units. So each triangle will have a base of 7 and height of 2.
A = 1/2 bh
A = 1/2 (7) (2)
A = 7
The area of the kite is double that, so:
2A = 14
Answer:
Step-by-step explanation:
Answer:(A)= (-x^11)/(y^7)
(B)= (1/12xy^5)
Step-by-step explanation:
(A) (3x^3y^-2)(-2x^-3y^2)^-5/(6x^7y^-5)
[(3x^3y^-2)(-2x^15y^-10)]/(6x^7y^-5)
(6x^18y^5)/(-6x^7y^12)
(-6x^11)/(6y^7)
(-x^11)/(y^7)
(B) [(12x^-3y^5)/(x^-4)]^-1
(1/12xy^5)
first off let's notice that hmmm the vertex is above the point (3,-3), so if we "assume" is a vertical parabola, then it'd be opening downwards.... anyhow that said, let's plug in those values.
![\bf ~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Bvertical%20parabola%20vertex%20form%7D%20%5C%5C%5C%5C%20y%3Da%28x-%20h%29%5E2%2B%20k%5Cqquad%20%5Cbegin%7Bcases%7D%20%5Cstackrel%7Bvertex%7D%7B%28h%2Ck%29%7D%5C%5C%5C%5C%20%5Cstackrel%7B%22a%22~is~negative%7D%7Bop%20ens~%5Ccap%7D%5Cqquad%20%5Cstackrel%7B%22a%22~is~positive%7D%7Bop%20ens~%5Ccup%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
![\bf vertex~~(\stackrel{h}{2}~~,~~\stackrel{k}{1})\qquad \implies \qquad y = a(x-2)^2+1 \\\\\\ \stackrel{\textit{we also know that }}{(3~~,~~-3)} \begin{cases} x = 3\\ y = -3 \end{cases}\qquad \implies -3=a(3-2)^2+1 \\\\\\ -3=a(1)^2+1\implies -3=a+1\implies -4=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y = -4(x-2)^2+1~\hfill](https://tex.z-dn.net/?f=%5Cbf%20vertex~~%28%5Cstackrel%7Bh%7D%7B2%7D~~%2C~~%5Cstackrel%7Bk%7D%7B1%7D%29%5Cqquad%20%5Cimplies%20%5Cqquad%20y%20%3D%20a%28x-2%29%5E2%2B1%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bwe%20also%20know%20that%20%7D%7D%7B%283~~%2C~~-3%29%7D%20%5Cbegin%7Bcases%7D%20x%20%3D%203%5C%5C%20y%20%3D%20-3%20%5Cend%7Bcases%7D%5Cqquad%20%5Cimplies%20-3%3Da%283-2%29%5E2%2B1%20%5C%5C%5C%5C%5C%5C%20-3%3Da%281%29%5E2%2B1%5Cimplies%20-3%3Da%2B1%5Cimplies%20-4%3Da%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20y%20%3D%20-4%28x-2%29%5E2%2B1~%5Chfill)
