All categories

3 years ago

Which of the following is a geometric series?

Mathematics

1 answer:

Alenkasestr [34]3 years ago

7 0

<h2>Answer:</h2>

The geometric series is:

2+14+98+686

<h2>Step-by-step explanation:</h2>

The geometric series is a series in which each term of the series is a constant multiple of the preceding term of the series.

6+13+20+27

This is not a geometric series but is a arithmetic series.

Since, each term is increased from the preceding term by 7.

Since, 6+7=13

13+7=20

20+7=27

7+21+35+45

This is not a geometric series.

Since 7×3=21

But 21×3=63

But the next term that is given is: 28 and not 63

14+21+28+35

This is a arithmetic sequence.

Since

14+7=21

21+7=28

and 28+7=35

2+14+98+686

This is a geometric sequence.

Since,. we get a common ratio i.e. a term which when multiplied to each term of sequence gives the next term of the series.

i.e. 2×7=14

14×7=98

98×7=686

You might be interested in

Write a multiplication sentence that proves the division sentence -30/5 = -6 is correct.

Mrrafil [7]

Answer:

he believed governing is very hard and needs help

7 0

2 years ago

Read 2 more answers

Order the fractions from least to greatest 1/6, 2/5, 3/5, 3/7. Please show work TY

german

The order will be 1/6 2/5 3/7 3/5

7 0

3 years ago

A mixture of 30 pounds of candy sells for $1.10 a pound. The mixture consists of chocolates worth $1.50 a pound and chocolates w

Allushta [10]

Answer: Option 'B' is correct.

Step-by-step explanation:

Number of pounds of candy = 30

Cost per pound = $1.10

Total amount would be

$30\times 1.10\\\\=33$

Let the number of pound that sold at $1.50 per pound be 'x'.

Let the number of pound that sold at 90 cents per pound be '30-x.

According to question, we get that

$1.5x+0.90(30-x)=33\\\\1.5x+27-0.90x=33\\\\1.5x-0.9x=33-27\\\\0.6x=6\\\\x=\dfrac{6}{0.6}=10$

Hence, there are 10 pounds of chocolates worth $1.50 per pound.

Therefore, Option 'B' is correct.

8 0

3 years ago

What binomial do you have to add to the polynomial:

marshall27 [118]

Answer:

a) $-2x^2+5xy$

b) $-3y^2+5xy$

Step-by-step explanation:

Given polynomial : $2x^2+3y^2-5xy+1$

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable x is:

$-2x^2+5xy$

$(2x^2+3y^2-5xy+1)+(-2x^2+5xy)$

$=2x^2+3y^2-5xy+1-2x^2+5xy$

$=2x^2-2x^2+3y^2-5xy+5xy+1$

$=3y^2+1$

Given polynomial : $2x^2+3y^2-5xy+1$

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable y is:

$-3y^2+5xy$

$(2x^2+3y^2-5xy+1)+(-3y^2+5xy)$

$=2x^2+3y^2-5xy+1-3y^2+5xy$

$=2x^2+3y^2-3y^2-5xy+5xy+1$

$=2x^2+1$

7 0

2 years ago

PLEASE HELP I HAVE NO IDEA WHAT IM DOING!!!

algol13

Answer: 28.26

Step-by-step explanation:

What your looking for is called the annulus (or the difference of two concentric circles). You can find the annulus by subtracting the area of the inner circle from the area of the outer circle. Volume of a circle= πr²

You are given the diameter in these problems, so you need radius.

For the first circle (8 in one) :

8/2=4 r=4

A=3.14(4)²

A=50.24

For the second one (10 in one) :

10/2=5 r=5

A=3.14(5)²

A=78.5

To find the measure of the annulus, you subtract those numbers, getting 28.26

8 0

4 years ago