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Natali [406]
3 years ago
8

Add up the amount of hours of filler Naruto has. Make sure to show your work!

Mathematics
2 answers:
andreyandreev [35.5K]3 years ago
7 0

Answer:

Are you talking about the anime-

Step-by-step explanation:

guapka [62]3 years ago
7 0

Answer

It gotta be more than a mil fr !!

Step-by-step explanation:

100 x 100 + 1 + 1 - a mil + 100 lol

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Find the value of x <br> A) 3<br> B) 14<br> C) 5<br> D) 2
vesna_86 [32]

Answer:

C) 5

Step-by-step explanation:

The measure of angle TSU is 75°. (180° - 105° because it is a flat angle)

The sum of all the angles of a triangle is 180° as well.

You can write an equation to solve for x.

12x + 9x + 75 = 180

Isolate x.

12x + 9x = 180 - 75

12x + 9x = 105

Add the 12 and the 9.

21x = 105

Find what x is.

x = 105 ÷ 21

x = 5

4 0
3 years ago
Marlo had $35 but then spent $5​m
Step2247 [10]

Answer:

$30

Step-by-step explanation:

All you do is subtract the 5 dollars that he spent from the 35 dollars he already had and you get $30!

6 0
3 years ago
Read 2 more answers
At what point does she lose contact with the snowball and fly off at a tangent? That is
postnew [5]

Answer:

α ≥ 48.2°

Step-by-step explanation:

The complete question is given as follows:

" A skier starts at the top of a very large frictionless snowball, with a very small initial speed, and skis straight  down the side. At what point does she lose contact with the snowball and fly off at a tangent? That is, at the  instant she loses contact with the snowball, what angle α does a radial line from the center of the snowball to  the skier make with the vertical?"

- The figure is also attached.

Solution:

- The skier has a mass (m) and the snowball’s radius (r).

- Choose the center of the snowball to be the zero of gravitational  potential. - We can look at the velocity (v) as a function of the angle (α) and find the specific α at which the skier lifts off and  departs from the snowball.

- If we ignore snow-­ski friction along with air resistance, then the one work producing force in this problem, gravity,  is conservative. Therefore the skier’s total mechanical energy at any angle α is the same as her total mechanical  energy at the top of the snowball.

- Hence, From conservation of energy we have:

                       KE (α) + PE(α) = KE(α = 0) + PE(α = 0)

                       0.2*m*v(α)^2 + m*g*r*cos(α) = 0.5*m*[ v(α = 0)]^2 + m*g*r

                       0.2*m*v(α)^2 + m*g*r*cos(α) ≈ m*g*r

                        m*v(α)^2 / r = 2*m*g( 1 - cos(α) )

- The centripetal force (due to gravity) will be mgcosα, so the skier will remain on the snowball as long as gravity  can hold her to that path, i.e. as long as:

                         m*g*cos(α) ≥ 2*m*g( 1 - cos(α) )

- Any radial gravitational force beyond what is necessary for the circular motion will be balanced by the normal  force—or else the skier will sink into the snowball.

- The expression for α_lift becomes:

                            3*cos(α) ≥ 2

                            α ≥ arc cos ( 2/3) ≥ 48.2°

4 0
3 years ago
Angelica has ten pounds of jelly beans. She wants to repackage the jelly beans into bags of size 2/3pound. How many basofiel bea
Tanzania [10]

Answer:

  • 15 bags

Step-by-step explanation:

  • Jelly beans weight = 10 pounds
  • Each bag = 2/3 pound

<u>Number of bags required:</u>

  • 10 ÷ 2/3 = 10 × 3/2 = 30/2 = 15 bags
6 0
3 years ago
What is the value of m? 3m+2-1/4m=1/2(m-5)
Vera_Pavlovna [14]

Answer:

m=-2

hope this helped:)

Brainliest?

6 0
3 years ago
Read 2 more answers
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