All categories

2 years ago

How much extra money do you need this month to cover these emergencies??? Help

Mathematics

1 answer:

victus00 [196]2 years ago

8 0

Answer:

Somewhere between three months and six months of basic living expenses in your emergency fund.

Average Monthly Expenses

$1,000.00

Existing Liquid Savings (Excluding Retirement)

$2,500.00

Easy: Three months, Average: Six months, Difficult: Nine months, Very Difficult: 12 months

You might be interested in

If x= -8 and y=-4, evaluate the expression.<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3x-4%7D%7By-3%7D" id="TexFormula1"

bagirrra123 [75]

Your answer would be 4.

If we substitute in x = -8 and y = -4 into the expression, we get:

$\frac{3(-8) - 4}{-4 - 3}$

This then becomes:

$\frac{-24 - 4}{-7}$ = $\frac{-28}{-7}$ = 4.

I hope this helps!

6 0

2 years ago

Sheila is ordering pizzas for a party. Each plain pizza costs $9.00, and each topping costs $1.50. The delivery charge is $3.00.

ivolga24 [154]

F(5)=$63.00 is the correct answer

4 0

2 years ago

Read 2 more answers

Find the distance of the line segment joining the two points (-4 /2 - /12) and (/32, 2/3)

astraxan [27]

Answer: $4\sqrt{3}$ .

Step-by-step explanation:

Distance formula : Distance between points (a,b) and (c,d) is given by :-

$D=\sqrt{(d-b)^2+(b-a)^2}$

Distance between points $(-4\sqrt{2},\sqrt{12}) \text{ and }(-\sqrt{32}, 2\sqrt{3})$ .

$D=\sqrt{(2\sqrt{3}-(-\sqrt{12}))^2+(-\sqrt{32}-(-4\sqrt{2}))}\\\\=\sqrt{(2\sqrt{3}+\sqrt{2\times2\times3})^2+(-\sqrt{4\times4\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}-\sqrt{2^2\times3})^2+(-\sqrt{4^2\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}+2\sqrt{3})^2+(-4\sqrt{2}+4\sqrt{2})^2}\\\\=\sqrt{(4\sqrt{3})^2+0}\\\\=4\sqrt{3}\text{ units}$

Hence, the correct option is $4\sqrt{3}$ .

3 0

3 years ago

Tesla Pipe Company is creating metal pipe for an underground pipe line. According to the specifications given to them, the insid

Aleks [24]

Answer:

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

What is y=3x^2-2 in vertex form

Nata [24]

$\bf \qquad \qquad \textit{parabola vertex form}
\\\\\\
y=a(x-{{ h}})^2+{{ k}}\\
x=a(y-{{ k}})^2+{{ h}}\qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-----------------------------\\\\
y=3x^2-2\iff y = 3(x-0)^2-2$

3 0

3 years ago