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ASHA 777 [7]
3 years ago
9

Which equation is y = 3(x – 2)2 – (x – 5)2 rewritten in vertex form?

Mathematics
1 answer:
Alenkinab [10]3 years ago
4 0
Y= 3( x -2 )² - ( x-5 )² = 3 ( x² - 4 x + 4 ) - ( x² - 10 x + 25 ) =
= 3 x² - 12 x + 12 - x² + 10 x - 25=
= 2 x² - 2 x - 13 =
= 2 ( x² - x + 1/4 - 1/4 ) - 13 =
= 2 ( x - 1/2 )² - 1/2 - 26/2 =  2 ( x - 1/2 )² - 27/2
Answer: D) 
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8090 [49]

Answer:

46

Step-by-step explanation:

You have to do IVU+TUI=TUV

so... x+49+x+63=106

5 0
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Help me on this question
NeX [460]

Answer:

x = 18

Step-by-step explanation:

Vertically Opposite Angles are equal..

so,

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What is the mean of these numbers ? <br> 2,8,4,6,5
MrRa [10]

Answer:

5 is the mean

Step-by-step explanation:

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3 years ago
If 1200 cm^2 of material is available to make a box with a square base and an open top find the largest possible volume of the b
strojnjashka [21]
Surface area of box=1200 cm² 
<span>Volume of box=s²h </span>
<span>s = side of square base </span>
<span>h = height of box </span>
<span>S.A. = s² + 4sh </span>
<span>S.A. = surface area or 1200 cm², s²
 = the square base, and 4sh = the four 'walls' of the box. </span>
<span>1200 = s² + 4sh </span>
<span>1200 - s² = 4sh </span>
<span>(1200 - s²)/(4s) = h </span>


<span>v(s) = s²((1200 - s²)/(4s)) </span>
<span>v(s) = s(1200 - s²)/4 . </span>
<span>v(s) = 300s - (1/4)s^3</span>

by derivating
<span>v'(s) = 300 - (3/4)s² </span>
<span>0 = 300 - (3/4)s² </span>
<span>-300 = (-3/4)s² </span>
<span>400 = s² </span>
<span>s = -20 and 20. </span>
again derivating
<span>v"(s) = -(3/2)s </span>
<span>v"(-20) = -(3/2)(-20) </span>
<span>v"(-20) = 30 </span>
<span>v"(20) = -(3/2)(20) </span>
<span>v"(20) = -30 </span>


<span>v(s) = 300s - (1/4)s^3 </span>
<span>v(s) = 300(20) - (1/4)(20)^3 </span>
<span>v(s) = 6000 - (1/4)(8000) </span>
<span>v = 6000 - 2000 
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Answer:

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