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3 years ago

3=7(4-2u)-6u can you help

Mathematics

2 answers:

Zina [86]3 years ago

5 0

u=5/4

Explanation:

distribute and simplify right side of equation

3= 28−14u −6u

3=28−20u

subtract 28 from both sides

3−28=−20u

−25=−20u

divide both sides by

−20/ −25 = u ⇒ u =54

sp2606 [1]3 years ago

3 0

Answer:

5/4

Step-by-step explanation:

, open the bracket

3=28-14u-6u

Collect like terms

3-28=-14u-6u

-25 =-20u

Divide both side by -20

u=-25/-20. Minus sign will cancel each other and reduce to the lowest term

u=5/4

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$A^0+P^0+B^0=180^0$ $\begin{gathered} \text{Where A}^0=\text{ unknown,} \\ P^0=80^0\text{ and,} \\ B^0=40^0 \\ A^0+80^0+40^0=180^0 \\ A^0+120^0=180^0 \\ A^0=180^0-120^0 \\ A^0=60^0 \end{gathered}$

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$\begin{gathered} \frac{\sin 60^0}{y}=\frac{\sin 80^0}{14} \\ \text{Crossmultiply,} \\ y\times\sin 80^0=14\times\sin 60^0 \\ \text{Didive both sides by }\sin 80^0 \\ y=\frac{14\times\sin 60^0}{\sin 80^0} \\ y=12.31m \end{gathered}$

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Therefore, the length of the wires are (9.14m and 12.31m).

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