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sattari [20]
2 years ago
11

Mark is paid semimonthly. his semi monthly salary is 1,389. what is his annual salary?​

Mathematics
1 answer:
sergeinik [125]2 years ago
5 0

Step-by-step explanation:

The answer should be 29,736

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John put away 36 of 48 shirts in his closet. Don has 84 shirts. If he put away the same percent, how many shirts did Don put in
Alexeev081 [22]

Answer:

63

Step-by-step explanation:

John's percentage:

36 and 48 have a common factor of 12 so divide both of them by 12.

36/12= 3 and 48/12=4 therefore

so 36/48= 3/4 which is 75% but we don't need to focus on the percent.

Don's no. of shirts:

we know Don has 84 shirts so we say

3/4 of 84= no. of shirts that Don put in his closet

84/4=21 21x3=63

Don put 63 shirts in his closet.

Hope that helped! Anymore questions just ask! :)

3 0
2 years ago
Can anyone help me please.
EleoNora [17]
2x +9 <0

x > -12

2x<-9

2x<-9/2  (9/2 = 4.5)


x >-12
 the answer is all integers between -12 and -4.5

-11, -10, -9, -8, -7, -6, -5

8 0
3 years ago
What should be done to both sides of the equation in order to solve p - 17 = -23?
professor190 [17]

Answer:

you want to "isolate"  the variable "p" sooo...

Step-by-step explanation:

add 17 to both sides of the equation....  so you get

p = -6  :)

7 0
2 years ago
Which expression is equivalent to
rodikova [14]

Step-by-step explanation:

\log_{12}\left(\dfrac{\frac{1}{2}}{8w}\right)=\log_{12}\left(\dfrac{1}{16w}\right)\qquad\text{use}\ a^{-1}=\dfrac{1}{a}\\\\=\log_{12}(16w)^{-1}\qquad\text{use}\ \log_ab^n=n\log_ab\\\\=-1\log_{12}(16w)\qquad\text{use}\ \log_a(bc)=\log_ab+\log_ac\\\\=-\left(\log_{12}16+\log_{12}w\right)=-\log_{12}2^4-\log_{12}w\qquad\text{use}\ \log_ab^n=n\log_ab\\\\=-4\log_{12}2-\log_{12}w

8 0
3 years ago
Solve using substitution <br> y= x+4<br> x-y= -4
never [62]
X-(x+4)=-4

X-x-4=-4
-4=-4

All real numbers
6 0
3 years ago
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