1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aniked [119]
3 years ago
14

Does this graph represent a function? Why or why not?

Mathematics
1 answer:
In-s [12.5K]3 years ago
8 0
B. No, because it fails the vertical line test.
You might be interested in
A bank is offering 2.5% simple interest on a savings account. If you deposit $5000, how much interest will you earn in 4 years?
weeeeeb [17]

Answer:

A = 2500 + 2500 · 0.06 · 4 = 3100

Step-by-step explanation:

5 0
2 years ago
At sea world San Diego kid are only allowed into the air bounce if they are between 37 and 61 inches tall they are only allowed
ss7ja [257]

Answer:

Step-by-step explanation:

a. For the Air Bounce, children must be at least 37 inches tall. If we let h denote the child's height in inches, this means h≥37. They are also not allowed to be more than 61 inches tall so h≤61. We say h≥37 and h≤61. (This can be written as a compound inequality, but that is not expected at grade 6)  

For the Tide Pool Climb, children are not allowed to be over 39 inches. Using h for the child's height, this is represented by h≤39. We should also write this as 0<h since a height cannot be zero or negative.

b. The allowable heights in inches for Air Bounce are shaded blue on the number line below (note that they include 37 inches and 61 inches). No negative numbers are included on the number line as this does not make sense for the context of height.  

   

 

The allowable heights for Tide Pool Climb are shaded purple on the number line below:

   

 

Although it is not possible for a child to be close to 0 inches tall, these numbers are shaded because they fit the inequality h≤39. No negative numbers (or 0) are plotted because they do not make sense in the context of height. So the graph shows heights satisfying 0<h and h≤39.

c. In order go on the Tide Pool Climb, a child cannot be over 39 inches in height. In order to go on the Air Bounce, a child has to be at least 37 inches tall but not more than 61 inches. So to go on both, a child must be at least 37 inches tall but not more than 39 inches: 37≤h and h≤39. These heights in inches are highlighted on the number line below:

   

 

Notice that the shaded parts of this number line are where the shaded parts of the two previous underlines overlap: this makes sense as we are looking for heights of those who can go on both rides.

              ( I hope this helps and please Rate this answer it would really mean a lot to me :) )

6 0
3 years ago
Anybody, please answer this for me. I'm not good at mathematics
Lostsunrise [7]
Well, its kind of obivious that 2x + 4 stands out, but I think you are asking why. Whereas all other lines shown are vertical or horizontal, 2x+4 is diagonal. 
3 0
3 years ago
Evaluate the double integral.
Fynjy0 [20]

Answer:

\iint_D 8y^2 \ dA = \dfrac{88}{3}

Step-by-step explanation:

The equation of the line through the point (x_o,y_o) & (x_1,y_1) can be represented by:

y-y_o = m(x - x_o)

Making m the subject;

m = \dfrac{y_1 - y_0}{x_1-x_0}

∴

we need to carry out the equation of the line through (0,1) and (1,2)

i.e

y - 1 = m(x - 0)

y - 1 = mx

where;

m= \dfrac{2-1}{1-0}

m = 1

Thus;

y - 1 = (1)x

y - 1 = x ---- (1)

The equation of the line through (1,2) & (4,1) is:

y -2 = m (x - 1)

where;

m = \dfrac{1-2}{4-1}

m = \dfrac{-1}{3}

∴

y-2 = -\dfrac{1}{3}(x-1)

-3(y-2) = x - 1

-3y + 6 = x - 1

x = -3y + 7

Thus: for equation of two lines

x = y - 1

x = -3y + 7

i.e.

y - 1 = -3y + 7

y + 3y = 1 + 7

4y = 8

y = 2

Now, y ranges from 1 → 2 & x ranges from y - 1 to -3y + 7

∴

\iint_D 8y^2 \ dA = \int^2_1 \int ^{-3y+7}_{y-1} \ 8y^2 \ dxdy

\iint_D 8y^2 \ dA =8 \int^2_1 \int ^{-3y+7}_{y-1} \ y^2 \ dxdy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ( \int^{-3y+7}_{y-1} \ dx \bigg)   dy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ( [xy^2]^{-3y+7}_{y-1} \bigg ) \ dy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ( [y^2(-3y+7-y+1)]\bigg ) \ dy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ([y^2(-4y+8)] \bigg ) \ dy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ( -4y^3+8y^2 \bigg ) \ dy

\iint_D 8y^2 \ dA =8 \bigg [\dfrac{ -4y^4}{4}+\dfrac{8y^3}{3} \bigg ]^2_1

\iint_D 8y^2 \ dA =8 \bigg [ -y^4+\dfrac{8y^3}{3} \bigg ]^2_1

\iint_D 8y^2 \ dA =8 \bigg [ -2^4+\dfrac{8(2)^3}{3} + 1^4- \dfrac{8\times (1)^3}{3}\bigg]

\iint_D 8y^2 \ dA =8 \bigg [ -16+\dfrac{64}{3} + 1- \dfrac{8}{3}\bigg]

\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{64-8}{3}\bigg]

\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{56}{3}\bigg]

\iint_D 8y^2 \ dA =8 \bigg [  \dfrac{-45+56}{3}\bigg]

\iint_D 8y^2 \ dA =8 \bigg [  \dfrac{11}{3}\bigg]

\iint_D 8y^2 \ dA = \dfrac{88}{3}

4 0
2 years ago
Ann is grouping 38 rocks. She can put them into groups of 10 rocks or as single rocks. what are the different ways Ann can group
PtichkaEL [24]
Color,size,type,smell, glows
3 0
3 years ago
Read 2 more answers
Other questions:
  • Nine more than three times x is at least 15
    15·2 answers
  • Please help me it urgent find the total area.
    6·1 answer
  • How much is 400.00 invested at 9% interest compounded continuously be worth after 3 years
    9·1 answer
  • What is the surface area of the given figure? 1008 cm2, 1728 cm2, 1392 cm 2, 1216 cm2
    5·1 answer
  • Yulian works at the zoo feeding the animals. He puts water in the elephant habitat at the beginning of the day. The table shows
    8·1 answer
  • Whats you suggestion on freeshavacado?
    10·2 answers
  • 1:Under what condition will the line px+py+r=0 mat be a normal to the circke x²+y²+2gx+2fy+c=0
    10·2 answers
  • What is -4 3/4 = x - 1 1/5
    6·1 answer
  • 5x+8y=62.9<br> x=4-y<br> please solve correctly using substitution
    10·2 answers
  • What is meaning of trigonometry ​
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!