0.5-2(0)^2
0.5-0
0.5
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Step-by-step explanation:
The sum of ages of two friends is 13 years.
The product of their ages is 42.
<em>Let the age of 1st friend and 2nd friend is x, y respectively.</em>
<em>1 st condition= The sum of ages of two friends is 13 y</em><em>r</em><em>s. </em>
i.e x+y = 13........ (I)
<em>2nd condition= The product of their ages is 42.</em>
i.e X*y = 42........(ii)
From equation (I)
X+y = 13
or, X = 13-y........ (iii)
<em>Putting the equation (iii) in equation (ii).</em>
X*y= 42
(13-y) * y = 42
13y - y^2 = 42





Either; y-6 = 0
y = 6
Or;
y-7=0
y = 7
<em>Keeping the value of y as "7" in equation (ii)</em>
x*y = 42
7x = 42
X = 42/7
Therefore, the value of X is 6.
Therefore, either 1st friend is 6 years and 2nd is 7 years.
<em><u>H</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>it </u></em><em><u>helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
x = -19/2 y = -33/2
Step-by-step explanation:
x - (3x + 12) = 7
x - 3x - 12 = 7
-2x - 12 = 7
-2x = 19
x = -19/2
x - y = 7
-19/2 - y = 7
-y = 33/2
y = -33/2