3 years ago

Does this graph represent a function? Why or why not?

Mathematics

1 answer:

In-s [12.5K]3 years ago

8 0

B. No, because it fails the vertical line test.

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Step-by-step explanation:

General Equation of circle is

$(x-x_1)^{2} +(y-y_1)^{2} = r^{2}$ ----------- (1)

Here

$(x_1, y_1)= (0, 0)$

Radius r is distance from origin (x1, y1) to point (x2, y2)=(-3, -6)

$r=\sqrt{(x_2-x_1)^{2} + (y_2-y_1)^{2} }$

$r= \sqrt{(-3-0)^{2} + (-6-0)^{2} }$

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Substituting values in equation (1)

$(x-0)^{2} +(y-0)^{2} =( \sqrt{45})^{2}$

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