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KIM [24]
3 years ago
15

You are planning the scale model of a town that you will build. For now, you are laying everything out on a coordinate plane as

shown. You want to draw Wooster Street so that it is perpendicular to Main Street. You know that Wooster Street will pass through the point (-3, 8.75). Find the equation of the line for Wooster Street so that it is perpendicular to Main Street. Explain your reasoning

Mathematics
1 answer:
Rina8888 [55]3 years ago
7 0

Answer:

3

Step-by-step explanation:

because if you look closely at the graph you see

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Which angels are corresponding angles
stellarik [79]

Answer:

B. 5 and 7

E. 1 and 3

F. 6 and 8

Step-by-step explanation:

The angles in matching corners are called corresponding angles.

7 0
3 years ago
Anita collects shells and stones in a ratio of 1:2.
omeli [17]

Answer:

The answer is 16 stones

Step-by-step explanation:

It's 8:16 because

8/1 = 8

and

2 x 8 = 16

To check your answer to see if its correct :

1/2 = 2

16/2=8

Hope this helps!! ;)

8 0
3 years ago
Simplify problem if possible
sergeinik [125]
\left(\frac{(x^4y^{-2})^4}{(2x^2)^2\cdot2x^0y^3}\right)^2=\\
\left(\frac{x^{16}y^{-8}}{4x^4\cdot2y^3}\right)^2=\\
\left(\frac{x^{16}y^{-8}}{8x^4y^3}\right)^2=\\
\left(\frac{x^{12}y^{-11}}{8}\right)^2=\\
\frac{x^{24}y^{-22}}{64}
3 0
4 years ago
A rectangular box with a volume of 784 ft3 is to be constructed with a square base and top. the cost per square foot for the bot
iVinArrow [24]
I think it is 15 so I don’t know that if it right
8 0
3 years ago
A space S is defined as S = {1, 3, 5, 7, 9, 11} , and three subsets as A = {1, 3, 5} , B = {7, 9, 11} , C = {1, 3, 9, 11} . Assu
Lina20 [59]

Answer:

a) 0.5

b) 0.5

c) 0.67

d) 1

e) 0.83

f) 0.67

Step-by-step explanation:

a)

P(A)=n(A)/n(S)

n(A)=number of outcomes in event A=3

n(S)= Total number of outcome of an experiment=6

P(A)=3/6=1/2=0.5

b)

P(B)=n(B)/n(S)

n(B)=number of outcomes in event B=3

P(B)=3/6=1/2=0.5

c)

P(C)=n(C)/n(S)

n(C)=number of outcomes in event C=4

P(C)=4/6=2/3=0.67

d)

A∪B= {1,3,5} ∪ {7,9,11}={1,3,5,7,9,11}

P(A∪B)=n(A∪B)/n(S)=6/6=1

e)

A∪C={1,3,5}∪{1,3,9,11}={1,3,5,9,11}

P(A∪C)=n(A∪C)/n(S)=5/6=0.83

f)

A-C={1,3,5}-{1,3,9,11}={5}

(A-C)∪B={5}∪{7,9,11}={5,7,9,11}

P((A-C)∪B)=n((A-C)∪B)/n(S)=4/6=2/3=0.67

8 0
4 years ago
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