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2 years ago

Please help I will give brainliest for honest answers

Mathematics

1 answer:

Vaselesa [24]2 years ago

3 0

Answer:

$408

Step-by-step explanation:

subtract 30 from 540 to get 510

then divide 510 by 5 or divide 510 by 100 then multiply by 20

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510 divided by 5 is 102

510 divided by 100 is 5.1 which then you multiply by 20 to get 102

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102 is equal to 20% of 510 so you subtract 510 by 102 to get 408

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Anni [7]

So first calculate root of 3 which is 1.732
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7 0

3 years ago

Read 2 more answers

Tristan has some dimes and some quarters. He has at least 20 coins worth at most $4.25 combined. If Tristan has 10 dimes, determ

Dovator [93]

Answer:

The maximum number of quarters that he could have is 13

Step-by-step explanation:

Let x represent the number of quarters he could have. If he has 10 dimes and has at least 20 coins, then

→ x + 10 >= 20

→ x >= 10 (1)

His coins worth at most $4.25. Also, it is known that 1 dollar is equal to 100 cents, 1 dime is equal to 10 cents and 1 quarter is equal to 25 cents.

→ (x * 25) + (10 * 10) <= (4.25 * 100)

→ 25x + 100 <= 425

→ 25x <= 325

→ x <= 13 (2)

If we combine the equation 1 and 2:

10 <= x <= 13

The maximum value of x is 13

7 0

3 years ago

In this line of circles, the ratio of red circles to blue circles is 1:3 How many more circles would need to be added to make th

zaharov [31]

Answer:

The number of red circles to be added would be equal to 8 times the original amount of red circles

Step-by-step explanation:

Let

x ----> the number of red circles

y ----> the number of blue circles

Originally

$\frac{x}{y}=\frac{1}{3}$

$y=3x$ ----> equation A

How many more circles would need to be added to make the ratio of red to blue 3:1

Let

n ----> the number of additional red circles

$\frac{x+n}{y}=\frac{3}{1}$ ----> equation B

substitute equation A in equation B

$\frac{x+n}{3x}=\frac{3}{1}$

solve for n

$x+n=9x\\n=9x-x\\n=8x$

therefore

The number of red circles to be added would be equal to 8 times the original amount of red circles

5 0

3 years ago

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frutty [35]

Answer:

1/2, 3

Step-by-step explanation:

This is a pretty involved problem, so I'm going to start by laying out two facts that our going to help us get there.

The Fundamental Theorem of Algebra tells us that any polynomial has as many zeroes as its degree. Our function f(x) has a degree of 4, so we'll have 4 zeroes. Also,
Complex zeroes come in pairs. Specifically, they come in conjugate pairs. If -2i is a zero, 2i must be a zero, too. The "why" is beyond the scope of this response, but this result is called the "complex conjugate root theorem".

In 2., I mentioned that both -2i and 2i must be zeroes of f(x). This means that both $x-2i$ and $x+2i$ are factors of f(x), and furthermore, their product, $x^2+4$ , is also a factor. To see what's left after we factor out that product, we can use polynomial long division to find that