All categories

2 years ago

How do you find a radius

Mathematics

2 answers:

nataly862011 [7]2 years ago

5 0

Answer:

Take the circumference of the circle and divide by two times pi for circle with a circumference of 15 you should divide by 15 by 2×3.14 and round the decimal point to your answer of approximately 2.39

Step-by-step explanation:

aleksandrvk [35]2 years ago

5 0

In a circle, if you drew a line that passed through both edges of the circle and through the center, that would be your diameter. The length from the center point to any point on the outside of the circle is called the radius, which happens to also be exactly 1/2 of the diameter. To find the radius, simply divide the length of the radius by 2 and that will give you the radius!

Hope this helps!

You might be interested in

What is the sales tax on the chair shown if the tax rate is 5.75% ( the chairs price is $178.90)

timurjin [86]

If I remember how to do this right I’m pretty sure you just divid by 178.90 by 5.75 wich gives you 31.11 for the tax rate

7 0

2 years ago

An architect wants to draw a rectangle with a diagonal of 13 centimeters. The length of the rectangle is to be 3 centimeters mor

butalik [34]

Answer:

The rectangle is 3.2 cm by 12.6 cm

Step-by-step explanation:

See attached image for a diagram.

Choose w to represent the width because the length is described by referring to the width: it's 3 more than (add 3) triple (multiplied by 3) the width.

Length = 3w + 3

The diagonal forms two right triangles, each with leg = w, other leg = 3w + 3, hypotenuse = 13.

The Pythagorean Theorem says $(\text{leg})^2+(\text{leg})^2=(\text{hypotenuse})^2$ so

$w^2+(3w+3)^2=13^2\\\\w^2+9w^2+18w+9=169\\\\10w^2+18w-160=0\\\\5w^2+9w-80=0\\$

Now solve using the Quadratic Formula with $a=5,\,b=9,\,c=-80$ .

$w=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\w=\frac{-9\pm\sqrt{81+1600}}{10}\\\\w=\frac{-9\pm\sqrt{1681}}{10}\\\\w=\frac{-9\pm41}{10}\\\\w=-5\text{ or }w=3.2$

The negative root makes no sense as a distance, so the width of the rectangle is 3.2 cm. The length is 3(3.2) + 3 = 12.6 cm.

5 0

2 years ago

If each 6 in. On the scale drawing below equals 3 feet, what is the actual area of the shape in square units?

Liono4ka [1.6K]

Answer:

32 ft²

Step-by-step explanation:

Assuming the diagram attached below similar to the one required to complete the question below.

From the diagram,

Actaul Area of a parallelogram (A) = Actual Base(b)× actual heigth(h)

A = bh.......................... Equation 1

From the question,

If each 6 in on the scale drawing equals 3 feet

Given:

base on the scale drawing = 8 in.

Actual base(b) = (8×3)/6 = 4 feet.

Height on the scale drawing = 16 in

Actual height(h) = (16×3)/6 = 8 feet.

Substitute these values into equation 1

A = 4×8

A = 32 ft²

Hence the actual area of the shape is 32 ft²

4 0

2 years ago

Dilate the trapezoid using center (-3,4) and scale factor 1/2.

pochemuha

The coordinates of the vertices of the image of the trapezoid are given as;

A'(x, y) = (- 4, 1), B'(x, y) = (- 2, 1), C'(x, y) = (- 5 / 2, 5 / 2) , D'(x, y) = (- 7 / 2, 5 / 2).

<h3>How to find the image of a trapezoid by dilation?</h3>

In this question we have a representation of a trapezoid, whose image has to be generated by a kind of rigid transformation known as dilation, whose equation is described :

P'(x, y) = O(x, y) + k · [P(x, y) - O(x, y)]

Where O(x, y) - Center of dilation

k - Scale factor

And P(x, y) - Coordinates of the original point, P'(x, y) - Coordinates of the resulting point.

Since k = 1 / 2, A(x, y) = (- 5, - 2), B(x, y) = (- 1, - 2), C(x, y) = (- 2, 1), D(x, y) = (- 4, 1), O(x, y) = (- 3, 4),

Therefore, the coordinates of the vertices of the image are:

Point A'

A'(x, y) = O(x, y) + k · [A(x, y) - O(x, y)]

A'(x, y) = (- 3, 4) + (1 / 2) [(- 5, - 2) - (- 3, 4)]

A'(x, y) = (- 3, 4) + (1 / 2) (- 2, - 6)

A'(x, y) = (- 3, 4) + (- 1, - 3)

A'(x, y) = (- 4, 1)

Point B';

B'(x, y) = O(x, y) + k [B(x, y) - O(x, y)]

B'(x, y) = (- 3, 4) + (1 / 2) [(- 1, - 2) - (- 3, 4)]

B'(x, y) = (- 3, 4) + (1 / 2) (2, - 6)

B'(x, y) = (- 3, 4) + (1, - 3)

B'(x, y) = (- 2, 1)

Point C';

C'(x, y) = O(x, y) + k · [C(x, y) - O(x, y)]

C'(x, y) = (- 3, 4) + (1 / 2) [(- 2, 1) - (- 3, 4)]

C'(x, y) = (- 3, 4) + (1 / 2) (1, - 3)

C'(x, y) = (- 3, 4) + (1 / 2, - 3 / 2)

C'(x, y) = (- 5 / 2, 5 / 2)

Point D'

D'(x, y) = O(x, y) + k [D(x, y) - O(x, y)]

D'(x, y) = (- 3, 4) + (1 / 2) [(- 4, 1) - (- 3, 4)]

D'(x, y) = (- 3, 4) + (1 / 2) (- 1, - 3)

D'(x, y) = (- 3, 4) + (- 1 / 2, - 3 / 2)

D'(x, y) = (- 7 / 2, 5 / 2)

To learn more on dilations:

brainly.com/question/13176891

#SPJ1

3 0

8 months ago

Which is equivalent to (2^-3)^4 1/2^12 2 -2^12 1/2^7

sleet_krkn [62]

Answer:

The answer is First option

1/2^12 .

$\frac{1}{2^{12} }$

Step-by-step explanation:

Given:

(2^-3)^4

i.e

$(2^{-3} )^{4}$

To Find:

$(2^{-3} )^{4}=?$

Solution:

Law of Indices

$(x^{a}) ^{b} =x^{a\times b}\\and\\x^{-1}=\frac{1}{x}$

Using the above Property we get

∴ $(2^{-3} )^{4}=2^{-3\times 4} \\\\ (2^{-3} )^{4}=2^{-12} \\\\(2^{-3} )^{4}= \frac{1}{2^{12} }$

The answer is First option

1/2^12 .

$(2^{-3} )^{4}=\frac{1}{2^{12} }$

6 0

3 years ago