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Jobisdone [24]
2 years ago
15

the temperature is changing everyday by -7/18 degrees Fahrenheit. what will be the change in the temperature after 3 days​

Mathematics
1 answer:
Yuki888 [10]2 years ago
8 0

Answer:a

Step-by-step explanation:

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Find the length of OC.
frosja888 [35]

Answer:

About 8

Step-by-step explanation:

I found this by doing 16 divided by 2 since half of 16 is 8and AC and OC are congruent so I think it is 8.

6 0
3 years ago
Read 2 more answers
Help me please. I am having troubles with my math homework.
jeyben [28]

Answer: (3) f(8) = g(8)

<u>Step-by-step explanation:</u>

Let's compare the values of f(x) and g(x) when x = 0, 2, 8, and 4

<u>      f(x)       </u>                      <u>      g(x)        </u>            <u>Comparison</u>

f(x) = 2x - 3                     g(x)=\dfrac{3}{2}x+1

f(0) = 2(0) - 3                     g(0)=\dfrac{3}{2}(0)+1

      = -3                                   = 1                     f(0) < g(0)

f(2) = 2(2) - 3                     g(2)=\dfrac{3}{2}(2)+1

     = 1                                      = 4                     f(2) < g(2)

f(8) = 2(8) - 3                     g(8)=\dfrac{3}{2}(8)+1

     = 13                                   = 13                     f(8) = g(8)

f(4) = 2(4) - 3                     g(4)=\dfrac{3}{2}(4)+1

      = 5                                   = 7                       f(4) < g(4)


The only statement provided that is true is f(8) = g(8)




3 0
3 years ago
Edward Winslow deposited $20,000 into a savings account paying 6% annual interest compounded monthly. What amount will be in the
horsena [70]

Answer:

its easy

Step-by-step explanation:

the answer is

hi

4 0
3 years ago
Find the value of c .<br> 5/2 = c/22<br> c = ___.
sleet_krkn [62]

Answer:

c = 55

Step-by-step explanation:

8 0
3 years ago
A tank contains 1000 L of pure water. Brine that contains 0.05 kg of salt per liter of water enters the tank at a rate of 5 L/mi
Margaret [11]

Answer:

a) y(t)=0.65\frac{Kg}{min}(tmin)

b) y(40)=26Kg

Step-by-step explanation:

Data

Brine a (Ba)

V_{Ba}=5\frac{Lt}{min}\\  Concentration(Bca)=0.05\frac{Kg}{Lt}

Brine b (Bb)

V_{Bb}=10\frac{Lt}{min}\\  Concentration(Bcb)=0.04\frac{Kg}{Lt}

we have that per every minute the amount of solution that enters the tank is the same as the one that leaves the tank (15 Lt / min)

, then the amount of salt (y) left in the tank after (t) minutes: y=V_{Ba}*B_{ca}+V_{Bb}*B_{cb}=5\frac{Lt}{min}*0.05\frac{Kg}{Lt}+10\frac{Lt}{min}*0.04\frac{Kg}{Lt}=\\0.25\frac{Kg}{min}+0.4\frac{Kg}{min}=0.65\frac{Kg}{min}

Finally:

a) y(t)=0.65\frac{Kg}{min}(tmin)

b) y(40)=0.65\frac{Kg}{min}(40min)=26Kg

being y(t) the amount of salt (y) per unit of time (t)

5 0
2 years ago
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